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myrzilka [38]
3 years ago
12

What is the first step to solve this equation: -3x + 12 = -40

Mathematics
2 answers:
ElenaW [278]3 years ago
7 0

Answer:

Your supposed to cancel out 12 on both sides so u subtract 12 on both sides so the equation would be

-3x= -52

Step-by-step explanation:

FinnZ [79.3K]3 years ago
5 0

Answer:

17.3333

Step-by-step explanation:

-3x+12=-40

3x=-40-12

3x=-52

x=52÷3

x=17.3333

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C and D

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I just need to know if these are parallel please,,,
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Find the difference quotient <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%20%2B%20h%29%20-%20f%28x%29%7D%7Bh%7D" id="TexFor
AlladinOne [14]

Answer:

-2x - h - 3

Step-by-step explanation:

Step 1: Define

Difference Quotient: \frac{f(x+h)-f(x)}{h}

f(x) = -x² - 3x + 1

f(x + h) means that x = (x + h)

f(x) is just the normal function

Step 2: Find difference quotient

  1. <u>Substitute:</u> \frac{[-(x+h)^2-3(x+h)+1]-(-x^2-3x+1)}{h}
  2. <u>Expand and Distribute:</u> \frac{[-(x^2+2hx+h^2)-3x-3h+1]+x^2+3x-1}{h}
  3. <u>Distribute:</u> \frac{-x^2-2hx-h^2-3x-3h+1+x^2+3x-1}{h}
  4. <u>Combine like terms:</u> \frac{-2hx-h^2-3h}{h}
  5. <u>Factor out </u><em><u>h</u></em><u>:</u> \frac{h(-2x-h-3)}{h}
  6. <u>Simplify:</u> -2x - h - 3

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Suppose that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water
Setler79 [48]

Answer:

Step-by-step explanation:

Given that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water is pumped into the tank at a rate of 4 gal/min, and when the solution is well stirred, it is then pumped out at the same rate.

Let Q(t) be the quantity of salt at time t.

Q(0) = 70 pounds

Inflow of water = outflow = 4 gal/min

So resulting volume of tank at time t = 400 gallons

Rate of change of salt = inflow - outflow

= 0 - \frac{Q(t)}{400}

i.e. \frac{dQ}{dt} =\frac{-Q(t)}{400}

This is a variable separable equation

\frac{dQ}{Q}=-\frac{dt}{400} \\ln Q = {-\frac{t}{400}} +C\\Q = A e^{-\frac{t}{400}}

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So A(t) = Q(t) = 70 e^{-\frac{t}{400}} and

A(0) = Q(0) = 70 lbs.

7 0
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