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Lina20 [59]
3 years ago
14

Can someone please help me with these two please I'll appreciate it :)

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0
4.

\sqrt{64}=8\\\\8\dfrac17=8.14285714...\\\\8.\overline{14}=8.14141414...\\\\ \dfrac{15}2=7,5\\\\\\ \boxed{\ \dfrac{15}2\ \ \textless \ \ \sqrt{64}\ \ \textless \ \ 8.\overline{14}\ \ \textless \ \ 8\dfrac17\ }

5.

\sqrt{18}  doesn't belong with the other three because it is irrational number
The other three can be expressed as a ratio between two <span>integers.

-\dfrac{10}2=\dfrac{-10\ }2\\\\-13.4=-13\frac4{10}=\frac{-134}{\ 10}\\\\ 22.\overline7=22\frac79=\frac{205}9\\\\\\ \sqrt{18}=\sqrt{9\cdot2}=\sqrt9\cdot\sqrt2=3\sqrt2
</span>

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Electrical resistance ina wire is directly proportional to its length and inversely proportional to the square of its diameter.
LenaWriter [7]
Initial Conditions:

length=L= 10 cm = (10*10⁻²)m
Diameter=D= 2 cm= (2*10⁻²)m
Radius= r= 0.01m
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So, from initial conditions we find resistivity(р)
                                       R=рL/A
                                       R*A /L=р
                                      (600)*(1.57*10⁻⁴)/(10*10⁻²)=р
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<span>As, material remains same so resistivity(p) doesn't change

 </span>Lenght= L1= 15 fm= 15*10⁻¹⁵ m
Diameter= D1 = 5 cm= 5*10⁻² m
Radius= r= 0.025 m
Area= A1= π*r²/2 =9.8125*10⁻⁴ m²
                                               R=р*L1/A1
                                               R=(0.942 )*(15*10⁻¹⁵ )/(9.8125*10⁻⁴)
                                               R=1.44*10⁻¹¹ Ω
3 0
3 years ago
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