Ask question

Ask question

All categories

3 years ago

14

Can someone please help me with these two please I'll appreciate it :)

1 answer:

s344n2d4d5 [400]3 years ago

7 0

4.

$\sqrt{64}=8\\\\8\dfrac17=8.14285714...\\\\8.\overline{14}=8.14141414...\\\\ \dfrac{15}2=7,5\\\\\\ \boxed{\ \dfrac{15}2\ \ \textless \ \ \sqrt{64}\ \ \textless \ \ 8.\overline{14}\ \ \textless \ \ 8\dfrac17\ }$

5.

$\sqrt{18}$ doesn't belong with the other three because it is irrational number
The other three can be expressed as a ratio between two <span>integers.

$-\dfrac{10}2=\dfrac{-10\ }2\\\\-13.4=-13\frac4{10}=\frac{-134}{\ 10}\\\\ 22.\overline7=22\frac79=\frac{205}9\\\\\\ \sqrt{18}=\sqrt{9\cdot2}=\sqrt9\cdot\sqrt2=3\sqrt2$
</span>

You might be interested in

What is 10.26 with 8% tax

sleet_krkn [62]

Answer:

$11.08 to the nearest penny

Step-by-step explanation:

So I do it like

10.26 is 100 percent

We’re adding 8 percent so technically multiplying by 108

SO 10.26*108 is 11.08 to the nearest penny

It so much easier, easy 1 step

8 0

3 years ago

Read 2 more answers

Plz help this question out

Elden [556K]

Answer:

bad in this..............

3 0

2 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

so

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago

I don't get the answer

Goshia [24]

A' is (-12, 6)
B' is (0,6)
C' is (3, -3)
D' is (-9, -3)

Hope this helps!

7 0

3 years ago

Please help me find the area of this shape

oee [108]

Answer:

Step-by-step explanation:

15 x 7 = 105

The gap is either 9 x 7 =63 or 12 x 7 = 84

105 - 84 = 21

105 - 63 = 42

So the shaded area is either is 21 or 42

7 0

2 years ago