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chubhunter [2.5K]
3 years ago
6

10

Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

SAS

Step-by-step explanation:

ok so there is one angle and 2 sides

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Use the figure below to answer the question. What is the measure of ∠ABC? *
Ronch [10]

Answer:

D 98°

Step-by-step explanation:

180-82 = 98 or the long way

3x+5 = 180-82

3x = 93

x = 31

3(31) + 5 = 98

4 0
3 years ago
Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $3,169 was collected on the sale of 1,325 ticket
eimsori [14]

Answer:

461 adults and 864 students

Step-by-step explanation:

We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 1,325 tickets were purchased, then s+a=1325.

We also know that a total of $3,169 was collected and adult tickets cost $5 each and students cost $1 each. We can write 1s+5a=3169.

We will solve by substituting one equation into the other. We first solve the first equation for s which is s=1325-a. Substitute s=1325-a into 1s+5a=3169. Simplify and isolate the variable a.

1(1325-a)+5a=3169

1325-a+5a=3169

1325+4a=3169

1325-1325+4a=3169-1325

4a=1844

a=461

This means that 461 adults attended and 864 students attended since 864+461=1325.

8 0
3 years ago
The supplementary angle of 100.6° is
Nuetrik [128]

It would be an obtuse angle

3 0
3 years ago
Sam opened a money-market account that pays 2% simple interest. He started the account with $7,000 and made no further deposits.
I am Lyosha [343]
I = prt
420 = 7000 x .02 x t
420 = 140 x t
420/140 = 140 x t /140
t = 3 years
8 0
3 years ago
6. An urn contains 15 red balls and 8 blue balls. In each draw, one ball is extracted at random. It is then returned to the urn,
Leviafan [203]

Answer:

P(C4) = 0.0711

Step-by-step explanation:

consider the first draw = 15/23  since it cannot be a blue ball

The second draw = 21/29 since 6 more red balls will be added after the draw since a blue ball cannot be drawn

the third draw = 27/35 since 6 more red balls will be added after each draw since a blue ball cannot be drawn

therefore the total number of red balls will be = 15 + 6 + 6 + 6 = 33 red balls after the 4th draw. the total ball now in the urn= 33 red + 4 blue = 41

Hence the probability of drawing a blue ball at the fourth draw after drawing red balls at the previous attempts = 8/41

P(C4) = P ( fourth ball is blue ) * P( first ball red)*P(second ball red) *P(third ball red )

= (8/41) * (15/23) * (21/29)* (27/35) = 0.0711

8 0
3 years ago
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