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mylen [45]
2 years ago
10

What division problem does the model show? (Giving Brainliest To Whoever Answers Good)

Mathematics
1 answer:
Jobisdone [24]2 years ago
4 0

Answer:

18÷18÷18

=0.05555555555

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Given the function f(x) = 4^x - 1, explain and show how to find the average rate of change between x = 1 and x = 4.
soldier1979 [14.2K]

Answer:

84

Step-by-step explanation:

f(1)=4^1 - 1 = 3

f(4) = 4^4 - 1 = 255

rate of change = \frac{f(x_2)-f(x_1)}{x_2-x_1}

(255 - 3) / (4 - 1) = 252 / 3 = 84

3 0
3 years ago
Someone please help me with this question please
iris [78.8K]

Answer:

32

Step-by-step explanation:

<em>The ray created by line BC has two </em><u><em>180° sides</em></u><em>. Side </em><em>AC</em><em> intersects this ray and forms two angles. We can find this second angle by subtracting </em><em>148 </em><em>from </em><em>180 </em><em>to get </em><em>32</em><em>.</em>

5 0
3 years ago
Read 2 more answers
Suppose that the average number of accidents occurring on a highway each day is 3.5. Find the probability that at least two acci
irina1246 [14]

Answer:

48 yards

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If f(x) = 2x6 + 3x5 – 1, then what is the remainder when f(x) is divided by<br> x + 1?
Alchen [17]
<h3>Answer:   -2</h3>

===============================================

Explanation:

We use the remainder theorem. This is the idea where if we divide P(x) over (x-k), then the remainder is P(k).

Comparing x+1 to x-k shows that k = -1

It might help to rewrite x+1 as x-(-1) to get it into the form x-k better.

Plug this k value into the function

f(x) = 2x^6 + 3x^5 - 1

f(-1) = 2(-1)^2 + 3(-1)^5 - 1

f(-1) = 2(1) + 3(-1) - 1

f(-1) = 2 - 3 - 1

f(-1) = -1 - 1

f(-1) =-2

The remainder is -2

We can confirm this through synthetic division or polynomial long division.

5 0
3 years ago
Jason correctly graphed an inequality as shown below
schepotkina [342]
4 < = x + 4 < = 8
4 - 4 < = x + 4 - 4 < = 8 - 4
0 < = x < = 4.......this matches ur graph

so ur expression is : x + 4

8 0
3 years ago
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