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Studentka2010 [4]
3 years ago
14

For the month of June, Marla May worked the following. Her hourly rate is

Mathematics
1 answer:
Komok [63]3 years ago
4 0

Answer:

Week #1: 40 hours multiplied by $9.45 = $378.00

Step-by-step explanation:

Straight time is easy, its just regular pay per hour. If she had gone over 40 that week, was a minor, didn't get her meal breaks, worked an overnight shift in a closed store that began on the last day of the week and ended the morning of the first day of a new week, and she worked a paid holiday that week, was reimbursed for her meal break hour because she couldn't leave the building... then you have some calculating to do..

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Answer:

423

Step-by-step explanation:

623+223=846/2=423

3 0
3 years ago
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Sever21 [200]

Answer:

<h2><u>2 miles per hour</u></h2>

Step-by-step explanation:

Speed = Distance / Time

If we measure distance in miles and time in hour, we will get the speed in miles per hour.

Distance = 1 + 2/3 miles, which expressed as an improper fraction is 5/3 miles.

Time = 50 minutes which expressed in hours will be 50/60 or 5/6 hours.

(You can also see that 10 minutes is 1/6 of an hour, hence 50 minutes is 5/6 of an hour)

Speed = Distance / Time

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We know that dividing by "a/b" is same as multiplying by "b/a"

Hence, we have:

Speed = (5/3) * (6/5)

         = (5 * 6) / (3 * 5)

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4 0
3 years ago
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If sin(2x) = cos(x + 30°), what is the value of x?
valkas [14]

Answer:

x = -10 ° + π/6 + (2 π n_1)/3 for n_1 element Z

or x = 30 ° + π/2 + 2 π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

sin(2 x) = cos(x + 30 °)

Rewrite the right hand side using cos(θ) = sin(θ + π/2):

sin(2 x) = sin(30 ° + π/2 + x)

Take the inverse sine of both sides:

2 x = -30 ° + π/2 - x + 2 π n_1 for n_1 element Z

or 2 x = 30 ° + π/2 + x + 2 π n_2 for n_2 element Z

Add x to both sides:

3 x = -30 ° + π/2 + 2 π n_1 for n_1 element Z

or 2 x = 30 ° + π/2 + x + 2 π n_2 for n_2 element Z

Divide both sides by 3:

x = -10 ° + π/6 + (2 π n_1)/3 for n_1 element Z

or 2 x = 30 ° + π/2 + x + 2 π n_2 for n_2 element Z

Subtract x from both sides:

Answer:  x = -10 ° + π/6 + (2 π n_1)/3 for n_1 element Z

or x = 30 ° + π/2 + 2 π n_2 for n_2 element Z

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