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drek231 [11]
3 years ago
7

This data gives the average number of hours of exercise each week for different students.

Mathematics
1 answer:
vazorg [7]3 years ago
7 0

Answer:

                                       X

                                       X             X

              X                      X             X

 X    X    X              X     X             X

3.3  3.4  3.5  3.6  3.7  3.8  3.9  4.0

I believe that this is the answer

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Help with number two
BabaBlast [244]

Answer:

y = -2x+1

Step-by-step explanation:

We have a point and a slope, so we can use the point slope form of a line

y-y1 = m(x-x1)  where m is the slope and (x1,y1) is the point

y-3 = -2(x--1)

y-3=-2(x+1)

Distribute the 2

y-3 = -2x-2

Add 3 to each side

y-3+3 = -2x-2+3

y = -2x+1

This is in slope intercept form

7 0
3 years ago
What is the meaning of the underlined digit 648? The underlined number is 4 on the question
Kryger [21]
It mean 40 because it is in the tens place
~Jz
5 0
4 years ago
Read 2 more answers
At the beach, 29% of people are on the boardwalk and 26% are on the sand. If the rest are in the water, what percentage of peopl
natali 33 [55]

Answer:

45% of the people are in the water

Step-by-step explanation:

100%-29%=71%

71%-26%=45%

6 0
3 years ago
Whats complex number ​
Alex

Answer:

Complex numbers are numbers that consist of two parts — a real number and an imaginary number.

3 0
3 years ago
Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)
JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is \left(\frac{-9}{2}, \frac{-3}{2}\right)

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by:

\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9

Plugging in the values in formula, we get,

\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}

Hence, the midpoint of the segment is \left(\frac{-9}{2}, \frac{-3}{2}\right)

6 0
3 years ago
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