Answer:
sinѲ = -1/√5 or -√5/5
Step-by-step explanation:
On the Cartesian plane, we have radius (r) and angle (Ѳ) theta.
On the Cartesian plane we also have x, y where:
x = r cosѲ .......Equation 1
and y = r sinѲ ........Equation 2
r = √x² + y²
In the question we are given points (2,-1)
Where x = 2 , y = -1
We would solve for r by substituting 2 for x and -1 for y
r = √ 2² + -1²
r = √ 4 + 1
r = √5
In the question, we were asked to find what sin theta (Ѳ) is. Hence, we would be substituting √5 for r in Equation 2
y = r sinѲ
Where y = -1 and r = √5
-1 = √5 sinѲ
Divide both sides by √5
sinѲ = -1/√5
We can also represent sin Ѳ in a proper form, by multiplying both top and bottom by √5
sinѲ = -√5/5
Therefore, sinѲ = -1/√5 of -√5/5
Answer:
-6
Step-by-step explanation:
f(x) = -x-1
Find f(5), <u><em>this means that anywhere you see </em></u><u><em>x</em></u><u><em>, you substitute in </em></u><u><em>5</em></u><u><em>.</em></u>
f(x) = -x-1
f(5) = -(5)-1
<u>Take note of the signs.</u>
f(5) = -6
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(2+5x)=(4x+7)
-4x on each side
-2 in each side
x=5
Answer: It is the distance that -5 is form 0 on the number line
Step-by-step explanation:
We can define the absolute value of any number:
IxI as:
"The distance between the point x and the origin in the coordinate axis"
If we are in one dimension, x is just a value, and the coordinate axis will be a number line.
Then we could rewrite this as:
"is the distance between the value x and the 0 in the number line"
So:
IxI = x if x > 0
IxI = -x if x < 0.
Then:
I -5 I
Is the distance between the number -5, and the 0 in the number line, and this is:
I - 5 I = 5.
The correct option is:
"It is the distance that -5 is form 0 on the number line"
Actually there are three types of construction that were never accomplished by Greeks using compass and straightedge these are squaring a circle, doubling a cube and trisecting any angle.
The problem of squaring a circle takes on unlike meanings reliant on how one approaches the solution. Beginning with Greeks Many geometric approaches were devised, however none of these methods accomplished the task at hand by means of the plane methods requiring only straightedge and a compass.
The origin of the problem of doubling a cube also referred as duplicating a cube is not certain. Two stories have come down from the Greeks regarding the roots of this problem. The first is that the oracle at Delos ordered that the altar in the temple be doubled over in order to save the Delians from a plague the other one relates that king Minos ordered that a tomb be erected for his son Glaucus.
The structure of regular polygons and the structure of regular solids was a traditional problem in Greek geometry. Cutting an angle into identical thirds or trisection was another matter overall. This was necessary to concept other regular polygons. Hence, trisection of an angle became an significant problem in Greek geometry.
