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AVprozaik [17]
3 years ago
9

Which of the following were the two types of constructions that were never accomplished by the Greeks using only a compass and s

traightedge?
Mathematics
2 answers:
Kisachek [45]3 years ago
6 0
Actually there are three types of construction that were never accomplished by Greeks using compass and straightedge these are squaring a circle, doubling a cube and trisecting any angle. 

The problem of squaring a circle takes on unlike meanings reliant on how one approaches the solution. Beginning with Greeks Many geometric approaches were devised, however none of these methods accomplished the task at hand by means of the plane methods requiring only straightedge and a compass.

The origin of the problem of doubling a cube also referred as duplicating a cube is not certain. Two stories have come down from the Greeks regarding the roots of this problem. The first is that the oracle at Delos ordered that the altar in the temple be doubled over in order to save the Delians from a plague the other one relates that king Minos ordered that a tomb be erected for his son Glaucus.

The structure of regular polygons and the structure of regular solids was a traditional problem in Greek geometry. Cutting an angle into identical thirds or trisection was another matter overall. This was necessary to concept other regular polygons. Hence, trisection of an angle became an significant problem in Greek geometry.  
bazaltina [42]3 years ago
6 0

Answer:

for me the answer on apex was trisecting any angle and also doubling a cube there was only two

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A piece of licorice is to be cut into 10 equal size pieces . If the length of the piece of licorice is 2/3 yard, how long will e
Juliette [100K]
The first thing to do is turn this into an equation: 
2/3 ÷ 10 

10 as a fraction is 10/1
2/3 ÷ 10/1 = 

Fractional division is just fractional multiplication after switching the numerator and the denominator of the second fraction: 
2/3 X 10/1 

Fractional multiplication is simply multiplying the numerators by each other, and the denominators by each other: 
2 X 10 = 20
3 X 1 = 3

20/3

Each piece of liquorice will be 20/3 or 6 2/3 of a yard long. 

8 0
3 years ago
Solve: |x-2|=3 <br> Can someone explain how to do this please!!!
tia_tia [17]

Step-by-step explanation:

after x^2-4x-5 do sum and product

8 0
2 years ago
Complete the following proof Given: is the midpoint of , is the midpoint of Prove: =2
Vesnalui [34]

Answer:

Step-by-step explanation:

                        Statements                                    Reasons

1). M is the midpoint of segment AB        1). Given

   B is the midpoint of segment MD      

2). AM = MB and MB = BD                        2). Definition of midpoint

3). MD = MB + BD                                      3). Segment Addition Postulate

4). MD = MB + MB                                     4). Substitution property of of Equality

5). MD = 2MB                                            5). Simplify

Therefore, if M is the midpoint of segment AB, B is the midpoint of MD then MD = 2MB

5 0
2 years ago
What is the value of x and the length of segment DE?
disa [49]

Answer:

x  = 6.6 and DE = 16.2

Step-by-step explanation:

The question is incomplete as the attachment to solve segment DE is missing. However, see attached for complete question.

Given

\frac{5}{9}= \frac{9}{(2x+3)}

Required

Find x

Length of DE

To find x, we need to first simplify the given equation

\frac{5}{9}= \frac{9}{(2x+3)}

Multiply both sides by 9(2x+3)

\frac{5}{9} * 9(2x + 3) = \frac{9}{(2x+3)} * 9(2x + 3)

5(2x + 3) = 9(9)

10x + 15 = 81

Subtract 15 from both sides

10x + 15 - 15 = 81 - 15

10x  = 66

Divide both sides by 10

\frac{10x}{10}  = \frac{66}{10}

x  = \frac{66}{10}

x  = 6.6

From the attached;

DE = 2x + 3

Substitute 6.6 for x

DE = 2(6.6) + 3

DE = 13.2 + 3

DE = 16.2

Hence x  = 6.6 and DE = 16.2

3 0
3 years ago
3/4+ (1/3 divided by 1/6) - (- 1/2)
Virty [35]

Answer:

3 1/4

Step-by-step explanation:

3/4 + (1/3 divided by 1/6) - (- 1/2)

first calculate between the brackets.

(1/3) / (1/6)

Division is the inverse of multiplying.

(1/3) * (6/1)

multiply both numerators and multiply both denominators

1*6 / 3*1 = 6/3 = 2

3/4 + (2) - (- 1/2)

make all denominators into 4

3/4 + (8/4) - (- 2/4)

- ( - = plus

3/4 + (8/4) + 2/4

3/4 + 8/4 + 2/4

add all numerators since the denominators are all the same.

( 3 + 8 + 2 ) / 4

13/4

3 1/4

3.25

5 0
2 years ago
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