Question

Help !!!See question in image.Please show workings .​

Answer 1

Answer:

see explanation

Step-by-step explanation:

Given f(x) then the derivative f'(x) is

f'(x) = lim(h tends to 0 ) $\frac{f(x+h)-f(x)}{h}$

      = lim ( h to 0 ) $\frac{4(x+h)^2-2-(4x^2-2)}{h}$

      = lim ( h to 0 ) $\frac{4(x+h)^2-2-4x^2+2}{h}$

      = lim( h to 0 ) $\frac{4x^2+8hx+4h^2-4x^2}{h}$

      = lim( h to 0 ) $\frac{8hx+4h^2}{h}$

      = lim ( h to 0 ) $\frac{4h(2x+h)}{h}$ ← cancel h on numerator/ denominator

      = lim ( h to 0 )  4(2x + h) ← let h go to zero

f'(x) = 8x