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Novosadov [1.4K]
4 years ago
14

Ellen thinks that if a line has no slope, then it never touches the y-axis. Which line proves that her statement is incorrect?

Mathematics
2 answers:
vladimir2022 [97]4 years ago
8 0

Answer:

You know that having 0 as a slope is a horizontal line, so it touches the y-axis at y=1.

Step-by-step explanation:

Seriously, that line touches everything.

Fiesta28 [93]4 years ago
5 0
Y=1






Y=1 because then it is saying that the line is touching the y axes at 1
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F=-GMn/D^2 solve for M
notka56 [123]
M=FD^2/(-Gn) 
here is the solution 

5 0
3 years ago
Which line represents the direct variation equation y = 1/2x?
Verdich [7]

Answer:

C.

Step-by-step explanation:

y = 1/ x must pass through the origin because when x = 0, y = 0.

So its either B or C.

A positive slope rises to the right ( 1/2  is positive), so its C.

You can also see that the slope of C is 1/2 because it passes through the points (0.0) and (2, 1).

7 0
3 years ago
Read 2 more answers
In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
Calculate the unit price ($/g) of a 20g jar of sugar. The cost of a jar is $5.00.
BlackZzzverrR [31]

Answer:

$0.25/g

Step-by-step explanation:

20g --- $5.00

1g --- \frac{1}{20} × $5.00 = $0.25

7 0
3 years ago
Are the quadrilaterals similar? If so, give the scale factor. If not, explain.
castortr0y [4]
These are not similar.  For them to be similar, they need to exist in proportion to each other for every single side.  The ratio of the 12:9 sides is 4:3 when reduced.  The ratio of the other 2 sides is 5:3.  They all have to have the same ratio for them to be similar.
7 0
3 years ago
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