Answer:
4(x-7)^2-(x-7)+3 (Assuming t is f)
Step-by-step explanation:
Let s(x)=x-7 and t(x)=4x^2-x+3 .
(t o s)(x)=t(s(x))=t(x-7)
Before I continue this means replace the orginal x in t with x-7.
This will then give you
4(x-7)^2-(x-7)+3
The answer for this equation is x < 1
The answer will be the set of points that contains a different x value for each point.
We clearly see that for ever point in terms of CHOICE C the value of x is different.
Answer: Choice C
Just plot the values onto a normal number line
Answer:
At the end of the day 797 lockers were closed.
Step-by-step explanation:
So first of all you need to find out how many even numbers there are from 1-900 (which is 450) so you know that 450 are open. In the 3 multiplication tables every second number is even so you know that half of the 450 lockers that was opened was closed again: this meant that 225 lockers remained open.
You also know that every number in the 4 multiplication tables is the second number in the 2 multiplication tables so half of them are closed but you also know that the 900th locker was opened so now you have 113.
So to conclude you do 900-113 which gives you 797 (this is because 113 is the amount of lockers that is open)
