Answer:
its 273 rounded but say 270
Step-by-step explanation:
Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
Answer:
Sure! Your answer is about 315.33.
Step-by-step explanation:
If you want to figure this out by yourself, just open a calculator and do 946 * 0.33. You could also find this by dividing 946 by 3.
<em>Please</em><em> like</em><em> and</em><em> mark</em><em> brainliest</em><em>!</em>
<em>Hope</em><em> it</em><em> helps</em><em>!</em>
16,700,000,000,000,000 = 1.67 x 10^16
start at the last 0....count the number of spaces till u can get a decimal right after the first digit....thats 16 spaces. Now take ur numbers that are not 0...1.67....and multiply it by 10^16...because of the 16 spaces. I hope I am making some kind of sense...I am better at doing then explaining how to do...lol
