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3 years ago

If I had 4 eggs

Mathematics

2 answers:

Studentka2010 [4]3 years ago

7 0

Answer:

12 or 8

Step-by-step explanation:

iogann1982 [59]3 years ago

7 0

Answer:3 eggs

Step-by-step explanation:

You HAD 4 eggs

Leslie gives you 3 eggs

Roosters don’t lay eggs,

Therefore, you have 3 eggs.

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Solve this problem<br> √-16

a_sh-v [17]

Answer:

$4i$

Step-by-step explanation:

$\sqrt{-1} = i$

Therefore $\sqrt{-16} = \sqrt{16} \sqrt{-1} \\=4i$

3 0

3 years ago

If p+q has the value that is exactly 1/3 less than p what is the value of q

solmaris [256]

Answer:

q = - $\frac{1}{3}$ p

Step-by-step explanation:

$\frac{1}{3}$ less than p = $\frac{2}{3}$ p

Thus

p + q = $\frac{2}{3}$ p ( multiply through by 3 to clear the fraction )

3p + 3q = 2p ( subtract 3p from both sides )

3q = - p ( divide both sides by 3 )

q = - $\frac{1}{3}$ p

8 0

3 years ago

Suppose an airplane climbs 15 feet up for every 40 feet it moves forward. What is the slope of this airplanes ascent?

Anastasy [175]

the rise over run is 15/40 so the slope of the airplanes ascent is 0.375 feet per foot is move forward

5 0

3 years ago

Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D

viva [34]

Answer:

$\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C$

Step-by-step explanation:

So we have the indefinite integral:

$\int (\ln(x))^2dx$

This is the same thing as:

$=\int 1\cdot (\ln(x))^2dx$

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

$u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}$

Simplify:

$du=\frac{2\ln(x)}{x}dx$

And:

$dv=(1)dx\\v=x$

Therefore:

$\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx$

The x cancel:

$=x\ln(x)^2-\int2\ln(x)dx$

Move the 2 to the front:

$=x\ln(x)^2-2\int\ln(x)dx$

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

$=x\ln(x)^2-2\int 1\cdot\ln(x)dx$

Let u be ln(x) and let dv be (1)dx. Thus:

$u=\ln(x)\\du=\frac{1}{x}dx$

And:

$dv=(1)dx\\v=x$

So:

$=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)$

Simplify the integral:

$=x\ln(x)^2-2(x\ln(x)-\int (1)dx)$

Evaluate:

$=x\ln(x)^2-2(x\ln(x)-x)$

Now, we just have to simplify :)

Distribute the -2:

$=x\ln(x)^2-2x\ln(x)+2x$

And if preferred, we can factor out a x:

$=x(\ln(x)^2-2\ln(x)+2)$

And, of course, don't forget about the constant of integration!

$=x(\ln(x)^2-2\ln(x)+2)+C$

And we are done :)

8 0

3 years ago

Given: \overline{AE} \parallel \overline{FD},

MariettaO [177]

Answer:

See below for answer.

Step-by-step explanation:

∠ECB ≅ ∠FBC Parallel lines cut by a transversal form congruent alternate

interior angle

Δ AEC ≅ Δ DFB ASA

3 0

3 years ago