Answer:
<em>y=2 cos (π/4x-π/4)</em>
Step-by-step explanation:
<em>Given</em>
<em>A cosine function has an amplitude of 2, a midline of 5 and a period of 8.</em>
<em>To find: </em>
<em>A cosine function.</em>
<em>Explanation:</em>
<em>Let the function be,</em>
<em></em>
<em>Since amplitude is 2.</em>
<em>Then,</em>
<em></em>
<em>Also, since the period is 8.</em>
<em>Then,</em>
<em></em>
<em>And, since midline is 5.</em>
<em>Hence, the cosine function is,</em>
<em>y=2 cos (</em>
<em>x-</em>
<em></em>
Answer: 24,000
Step-by-step explanation:
SIRI
To solve this problem, what we have to do is to calculate
for the z scores of each condition then find the probability using the standard
normal probability tables for z.
The formula for z score is:
z = (x – u) / s
where,
x = sample value
u = sample mean = 23 days
s = standard deviation = 1 day
A. P when x < 21 days
z = (21 – 23) / 1
z = -2
Using the table,
P = 0.0228
Therefore there is a 2.28% probability that the hatching
period is less than 21 days.
B. P when 23 ≥ x ≥ 22
<span>z (x=22) = (22 – 23) / 1 = -1</span>
P (z=-1) = 0.1587
z (x=23) = (23 – 23) / 1 = 0
P (z=0) = 0.5
P = 0.5 - 0.1587 = 0.3413
Therefore there is a 34.13% probability that the hatching
period is between 22 and 23 days.
C. P when x > 25
z = (25 – 23) / 1
z = 2
P = 0.9772
This is not yet the answer since this probability refers
to the left of z. Therefore the correct probability is:
P true = 1 – 0.9772
P true = 0.0228
<span>Therefore there is a 2.28% probability that the hatching
period is more than 25 days.</span>
Answer:
D
Step-by-step explanation:
(-1) + (-1) = -2... so 500 times... it would be -500.
25 percent of the employees does not have company Health Insurance
