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adell [148]
3 years ago
12

How many planes appear in the figure?

Mathematics
2 answers:
Debora [2.8K]3 years ago
8 0

Answer:

where is the figure

Step-by-step explanation:

lapo4ka [179]3 years ago
5 0

There is no figure. You will have to take a picture to show us.

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Answer: 3
To check:
2 * 3 = 6
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Classify 3x^5-8x^3-2x^2+5 by number of terms.<br><br> Please show steps?
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The correct
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Simplify the expression to a + bi form:<br> (1 – 6i) + (12 + i)
Alenkasestr [34]

\\ \sf\longmapsto (1-6i)+(12+i)

\\ \sf\longmapsto 1-6i+12+i

\\ \sf\longmapsto 1+12-6i+i

\\ \sf\longmapsto 13-5i

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The perimeter of the rectangle below is 166 units. Find the length of side RS.
Wittaler [7]

The length of RS is 45 units if the perimeter of the rectangle below is 166 units.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

The question is incomplete.

The complete question is:

The perimeter of the rectangle below is 166 units. Find the length of the side RS. Write your answer without variables.

The figure is in the picture please refer to the picture.

The perimeter of the rectangle = 166 units

2(4x + 2 + 5x) = 166

9x + 2 = 83

9x = 81

x = 9

The length of RS = 5x = 5(9) = 45 units

Thus, the length of RS is 45 units if the perimeter of the rectangle below is 166 units

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ1

3 0
2 years ago
Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)
Lisa [10]

Answer:

f(x) = 4x^2 - 3x + 6

Step-by-step explanation:

Quadratic function is given as f(x) = ax^2 + bx + c

Let's find a, b and c:

Substituting (0, 6):

6 = a(0)^2 + b(0) + c

6 = 0 + 0 + c

c = 6

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

f(x) = ax^2 + bx + c

16 = a(2)^2 + b(2) + 6

16 = 4a + 2b + 6

16 - 6 = 4a + 2b + 6 - 6

10 = 4a + 2b

10 = 2(2a + b)

\frac{10}{2} = \frac{2(2a + b)}{2}

5 = 2a + b

2a + b = 5 => (Equation 1)

Substituting (3, 33), and c = 6

f(x) = ax^2 + bx + x

33 = a(3)^2 + b(3) + 6

33 = 9a + 3b + 6

33 - 6 = 9a + 3b + 6 - 6

27 = 9a + 3b

27 = 3(3a + b)

\frac{27}{3} = \frac{3(3a + b)}{3}

9 = 3a + b

3a + b = 9 => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

3a + b = 9

2a + b = 5

a = 4

Replace a with 4 in equation 2.

2a + b = 5

2(4) + b = 5

8 + b = 5

8 + b - 8 = 5 - 8

b = -3

The quadratic function that represents the given 3 points would be as follows:

f(x) = ax^2 + bx + c

f(x) = (4)x^2 + (-3)x + 6

f(x) = 4x^2 - 3x + 6

6 0
3 years ago
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