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kirill [66]
3 years ago
14

PLEASE HELP ASAP ON THESE TWO QUESTIONS BLESS YOUR HEART IF YOU HELP ME 9) Look for two points and find the sloope.

Mathematics
1 answer:
Alexxandr [17]3 years ago
5 0

Answer:

the two points are (-3,-3

Step-by-step explanation:

You must first check if the line is a straight line two the you check the intersection of the two points and the write it

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2( 10 - a^2 ) + 7a If ( a = 4 )Evaluate each expression
Lostsunrise [7]

Solution:

Given:

2(10-a^2)+7a

when a = 4, substitute for a in the expression;

\begin{gathered} 2(10-a^2)+7a=2(10-4^2)+7(4) \\ =2(10-16)+28 \\ =2(-6)+28 \\ =-12+28 \\ =16 \end{gathered}

Therefore, if (a = 4), then

2(10-a^2)+7a=16

Hence, the answer is 16.

6 0
1 year ago
Find the are of the shape below
skelet666 [1.2K]

Answer:

Area is 235

Step-by-step explanation:

Split the shape evenly so 11 x 14 and 9 x 9then multly and add

when slpitting up the number some times you have to add or subtract so to get 9 x 9 we just take 20 then take away 11 due to the line going through 20 and 20 - 11 = 9

9 x 9 = 81

11 x 14 = 154

81 + 154 = 235

or

Simular to the first one but the cutting line is different. this time the line cuts through 14

9 x 20 = 180

11 x 5 = 55

180 + 55 = 235

8 0
2 years ago
Need help on this thank you
krok68 [10]

Answer:

a=7

Step-by-step explanation:

24^2+a^2=25^2

576+a^2=625

49=a^2

a=7

5 0
3 years ago
Plsss help no spam.<br><br><br><br>.....................​
gregori [183]

Answer:

Third one.

x=6 y=12

Ok!

7 0
3 years ago
Read 2 more answers
Find the distance between the pair of points.
lana66690 [7]
\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ 0 &,& -11~) &#10;%  (c,d)&#10;&&(~ -9 &,& -12~)&#10;\end{array}&#10;\\\\\\&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;d=\sqrt{[-9-0]^2+[-12-(-11)]^2}&#10;\\\\\\&#10;d=\sqrt{(-9-0)^2+(-12+11)^2}&#10;\\\\\\&#10;d=\sqrt{(-9)^2+(-1)^2}\implies d=\sqrt{82}
3 0
3 years ago
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