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antoniya [11.8K]
3 years ago
14

Need help on this thank you

Mathematics
1 answer:
krok68 [10]3 years ago
5 0

Answer:

a=7

Step-by-step explanation:

24^2+a^2=25^2

576+a^2=625

49=a^2

a=7

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The base of a triangle is fixed at 2.218 millimeters. Determine the number of
harina [27]

When the base of a triangle is fixed at 2.218 millimeters, the area will be 0.1098 mm².

<h3>What will the area be?</h3>

It should be noted that the area of a triangle is calculated as:

Area of triangle = (1/2)×base×height

= (1/2) × 2.218 mm × 0.099 mm

= 1.109 mm × 0.099 mm

= 0.109791 mm²

≈ 0.1098 mm²

Therefore, the <em>area</em> is 0.1098 mm².

Learn more about triangles on;

brainly.com/question/2644832

#SPJ1

The base of a triangle is fixed at 2.218 millimeters. Determine the number of

significant figures of the area of the triangle with each given height of 0.099mm.

4 0
1 year ago
Mary is 5 feet tall and Alice is 1.6 meters tall. Who is taller? By how many inches?
8090 [49]

Answer:

Alice

Step-by-step explanation:

5 feet is approximately 1.5 meters so we can say Alice is taller than Mary by 10cm

6 0
3 years ago
Read 2 more answers
Jane, Jasmine, and Jocelyn have record collections. Jane has 3 times as many records as Jocelyn has. Jasmine has 2 more than twi
dangina [55]
X = jane, y = jasmine, z = jocelyn

x + y + z = 56
x = 3z
y = 2z + 2

3z + 2z + 2 + z = 56
6z + 2 = 56
6z = 56 - 2
6z = 54
z = 54/6
z = 9 <==== jocelyn

x = 3z
x = 3(9)
x = 27 <=== jane

y = 2z + 2
y = 2(9) + 2
y = 18 + 2
y = 20 <=== jasmine
7 0
3 years ago
Eli will photograph a wedding for a flat fee of $1000 or for an hourly rate of $120. For what lengths of time would the hourly r
Dennis_Churaev [7]
How long would it take $120/hr to add up to $1000?

Divide $1000 by $120/hr:  

 $1000
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$120/hr
8 0
3 years ago
What is the value of (7 + 2i)(3 - i)?
Harrizon [31]
There are two ways to work this out: normal variables or using "imaginary" numbers.

Normal variables:
(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}

Imaginary numbers:
Using the result from earlier:
21-i-2i^{2}
Now since i = \sqrt{-1}, then the expression becomes:
21-i-2i^{2}\\21-i-2(\sqrt{-1})^{2}\\21-i+(-2)(-1)\\21-i+2\\\\23-i
7 0
3 years ago
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