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Julli [10]
3 years ago
8

Work out 5 x 10^6 / 4 x 10^4 Give your answer as an ordinary number.

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
5 0

Answer:

1.25 \times  {10}^{2} = 125

Step-by-step explanation:

\frac{5 \times  {10}^{6} }{4 \times  {10}^{4} }  =  \frac{5}{4}  \times  \frac{ {10}^{6} }{ {10}^{4} }  = 1.25 \times  {10}^{2} = 125

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a) The average height of sunflowers in a field is 64 inches with a standard deviation of 3.5 inches. Describe a normal curve for
tresset_1 [31]
The values on the horizontal axis are:
at 0 = 64
at one standard deviation (lower, upper) = (60.5 , 67.5)
at two standard deviation (lower, upper) = (57 , 71)
at three standard deviation (lower, upper) = (53.5 , 74,5)

B. P(x > 71) = 1 - P(x < 71) = 1 - P[z < (71 - 64)/3.5] = 1 - P(z < 2) = 1 - 0.97725 = 0.02275
Therefore the no of plants taller than 71 inches will be approximately 0.02275 * 3000 = 68

8 0
3 years ago
3x<img src="https://tex.z-dn.net/?f=3x%5E%7B2%7D%20%3D27" id="TexFormula1" title="3x^{2} =27" alt="3x^{2} =27" align="absmiddle"
Kitty [74]

Answer:

3x3^2=27 but 3 x 9=27

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8 0
3 years ago
Read 2 more answers
Choose the equation of the line through (4, –5) and perpendicular to 6x + 12y = 13.
saw5 [17]

Answer:

Kotz I don’t know the answer because I’m to lazy to do it - but I need to talk to you again... it’s me Ellis - you don’t have to rejoin the server but message me 503 333 0177.

Step-by-step explanation:

5 0
3 years ago
Jaime has two fractio} , thns, 3/18 and 13/15 at he needs to compare. He knows he will not be able to tell which is bigger until
Mrrafil [7]
3/18 = 15/90
13/15 =78/90
To rewrite it as the same denominator you have to find a number that they both go into. So 90 is the lowest number that both 18 and 15 go into. 18 x 5 is 90 and 15 x 6 is 90 so what you do to the denominator you have to do to the numerator. So then you do 3 x 5 which equals 15 and you have to do 13 x 6 which equals 78. So the equation would end up being with the two fractions 15/90 and 78/90.
3 0
3 years ago
Barron's reported that the average number of weeks an individual is unemployed is 18.5 weeks. Assume that for the population of
Ket [755]

Answer:

A) The sampling distribution for a sample size n=50 has a mean of 18.5 weeks and a standard deviation of 0.849.

B) P = 0.7616

C) P = 0.4441

Step-by-step explanation:

We assume that for the population of all unemployed individuals the population mean length of unemployment is 18.5 weeks and that the population standard deviation is 6 weeks.

A) We take a sample of size n=50.

The mean of the sampling distribution is equal to the population mean:

\mu_s=\mu=18.5

The standard deviation of the sampling distribution is:

\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{50}}=0.849

B) We have to calculate the probability that the sampling distribution gives a value between one week from the mean. That is between 17.5 and 19.5 weeks.

We can calculate this with the z-scores:

z_1=\dfrac{X_1-\mu}{\sigma/\sqrt{n}}=\dfrac{17.5-18.5}{6/\sqrt{50}}=\dfrac{-1}{0.8485}=-1.179\\\\\\z_2=\dfrac{X_2-\mu}{\sigma/\sqrt{n}}=\dfrac{19.5-18.5}{6/\sqrt{50}}=\dfrac{1}{0.8485}=1.179

The probability it then:

P(|X_s-\mu_s|

C) For half a week (between 18 and 19 weeks), we recalculate the z-scores and the probabilities:

z=\dfrac{X-\mu}{\sigma/\sqrt{n}}=\dfrac{18-18.5}{6/\sqrt{50}}=\dfrac{-0.5}{0.8485}=-0.589

P(|X_s-\mu_s|

5 0
3 years ago
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