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borishaifa [10]
2 years ago
5

Find an equation in standard form for the ellipse with the vertical major axis of length 16 and minor axis of length 10.

Mathematics
2 answers:
Sedbober [7]2 years ago
7 0

Answer: The second answer

Step-by-step explanation:

Dimas [21]2 years ago
3 0

Answer:

<em>The first option. </em>

Step-by-step explanation:

You take the major vertical length and put it into this equation:

2a = 16

a/2 = 16/2

a = 8

You do the same with the minor length.

2b = 10

b/2 = 10/2

b = 5

You then switch the a^2 and the b^2 due to the fact that the veritcal length is longer than the horizontal. Then you use the formula to plug in 8 and 5.

(x - h)^2 / b^2 + (y - k)^2 / a^2 = 1

(x - h)^2 / 5^2 + (y - k)^2 / 8^2 = 1

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Answer: 5

Step-by-step explanation:

Range = highest value - lowest value

The highest value from the data set given = 1

The lowest value = -4

Therefore :

Range = 1 - (-4)

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Write an equation in slope-intercept form for the line that is parallel to the line y = -4x + 5 and that passes through the give
harkovskaia [24]
Since we know the slope intercept form is y=mx+b and that parallel lines have the same slope we know that the slope in our equation is going to be -4
we can plug in the point (-8,5) into y= -4x+b
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Step-by-step explanation:

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