Answer:
Consolation of Philosopy..
tan( tehta ) = 2/3
Sin( tetha ) = 2/√13
tan( tetha ) + Sin( tetha ) = 2/3 + 2/√13
= 2√13 + 6 / 3√13
Use Pythagorean theorem
a^2 + b^2 = c^2
a = 9, b = x, c = 18
9^2 + x^2 = 18^2
81 + x^2 = 324
x^2 = 243
x = 15.58846
Round to nearest tenth
Solution: x = 15.6
Answer:

Step-by-step explanation:
Hello,
Pls post the full question next time so that we can make sure what is expected.
I assume that you want to solve for (x,y)
(1) 2x + 3y = 7
(2) 3x + 2y = 8
2*(2)-3*(1) gives
2*3x + 2*2y - 3*2x - 3*3y = 2*8 - 3*7 = 16 - 21 = -5
6x - 6x + 4y -9y = -5
-5y=-5
y = 1
and we can replace in (1)
2x + 3*1 = 7
2x = 7 - 3 = 4
x = 2
hope this helps