(4y-3)(2y²+3y-5)
First , let's start with "4y"
4y*2y² = 8y³
4y*3y = 12y²
4y*-5 = -20y
Next, let's multiply by "-3"
-3*2y² = -6y²
-3*3y = -9y
-3*-5 = 15
Now, let's combine all of our values.
8y³+12y²-6y²-20y-9y+15 = 8y³+6y²-29y+15
4(c-6)
distribute 4(c-6)
4xc and -6x4
youll get 4c-24
C ) 131 is the answer
in the upside-vertex (not inverted) triangle, angle to your left hand side would be equal to x (as interior alternate angles) = 68
and the angle to the right would be 180-y= 180-117 = 163 (as linear angles)
so the angle at the vertex = 180 - (68 + 163) =49 (as angles in a triangle sum upto 180)
so the angle mz = 180 - 49 = 131 degrees (as linear pair of angles or angle in a straight line)
