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Morgarella [4.7K]
2 years ago
7

Help me plz thank you

Mathematics
1 answer:
nevsk [136]2 years ago
4 0

Answer:

1) Distance=Speed*time

90=(x+1)*(x)+(2x+5)(x-1)

90=x^2+x+2x^2-2x+5x-5

3x^2+4x-95=0

2) 3x^2+4x-95=0. Using quadratic formula, we get

x=(-4±sqrt(16-4*3*(-95)<u>)</u>)/6, x=5 or - 19/5 but since x also represents time, it can't be negative.

3) Total time take she took for the journey is x+x-1=2x-1=2*5-1=9 hours

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2/3 divided by 11/15
NNADVOKAT [17]
You need to implement the process of "flip-flop" and multiply which is where you flip the second fraction and multiply.

\frac{2}{3}÷\frac{11}{15}⇒\frac{2}{3}×\frac{15}{11}

Now you multiply across. 2×15=30 and 3×11=33

So now it is \frac{30}{33}

-----------------------------------------------------------
To reduce to the lowest terms, find the GCF common factor

The GCF is 3

Divide both the numerator and denominator by 3

\frac{30}{33}÷\frac{3}{3}=\frac{10}{11}

Answer: \frac{10}{11}

7 0
3 years ago
PLEASE HELP!!! WILL MARK AS BRAINLISTS!!!
Serjik [45]

The limit is x---->4-

The negative show that x approaches from the left

Now

As x approaches 4 from the left ... Means This number should be less than 4 (<4) but really close to 4.

Let's pick a Number

Say 3.99

Substitute this... You have

3.99/3.99-4

3.99/-0.01

If we choose x to be 3.999

we will have

3.999/-0.001

Notice the pattern... As x approaches 4 from the left... This limit will approach NEGATIVE INFINITY

Why?

As you approach 4 from the left... 3.9,3.99,3.999... You notice that the denominator becomes negative and EXTREMELY SMALL... and when you divide by an extremely small Number..... You'll get a relatively HUGE VALUE(You can try this... Use a calc... Divide any number of choice by a very small number... say.. 0.0000001.... You'll get a huge result

In our case... The denominator is negative... So it Will Approach a very Huge Negative Number

Hence

Answer.. X WILL APPROACH NEGATIVE INFINITY.

Vertical asymptotes are the zeroes of the denominator of a function

The denom. is x-4

Equate to zero to get the asymptote

x-4=0

x=4

Hence... There will be a vertical asymptote at x=4.

Have a great day!

7 0
3 years ago
Mumu + mumu=-----------
Morgarella [4.7K]
The answer is umu( M + m )
4 0
3 years ago
What is the answer to 6x5x3=
Otrada [13]

Answer:

90

Step-by-step explanation:

on multiplication.

6 0
2 years ago
Read 2 more answers
Explain how you know if an equation has no solutions, one solution or an infinite number of solutions
topjm [15]

Answer:

If you cancel out all of the x terms via addition or subtraction, and you get something along the lines of 1 = 2, then you have no solution.

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If you cancel out all the x terms via addition or subtraction and you get something along the lines of 1 = 1, then you have infinite solutions.

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x = 2n*pi, where n is some integer

5 0
2 years ago
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