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2 years ago

Xy(3x2+2x−3y)

Mathematics

1 answer:

timurjin [86]2 years ago

4 0

Xy (3x2+2x-3y)

6xy + 2x^2y- 3xy^2

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Find two numbers whose sum is 0 and who's difference is 8

timofeeve [1]

4 and -4 (in that order specifically)

4 + -4 = 4 - 4 = 0
4 - -4 = 4 + 4 = 8

6 0

3 years ago

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Someone ols help tysm if you dk im new :D

den301095 [7]

Answer:

-35-6=-41

that's the answer

4 0

2 years ago

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What is 1/12 (12-v)=1/6(v-6)

8_murik_8 [283]

Assuming you want to know the value of " $v$ "

So, step one we would have solve from the same value

$\frac{1}{12}(12-v) = \frac{1}{6}(v-6)\\ \frac{1}{12}(12) + \frac{1}{12} (-v) = \frac{1}{6}(v)+ \frac{1}{6} (-6) \\ 1 + \frac{-1}{12}(v) = \frac{1}{6}v + -01 \\ \frac{-1}{12} (v) +1 = \frac{1}{6} - 1$

Step two we have to subtract by $\frac{1}{6}v$ on each of your sides (so it can kind of be easier for you to solve)

So, $\frac{1}{6} v + 1 - \frac{1}{6}v = \frac{1}{6}v - 1 \frac{1}{6}v$
You would have to cancel out the right side because it would give you a(n) answer of 1

Now that we got those steps out of your way, let's subtract 1 to your sides that we're working with

$\frac{-1}{4}(v) +1 -1 \\ = -1 -1$

Finally we're close to our answer for $v$

$\frac{-1}{4}(v)= 2$

$\frac{4}{1} ( \frac{-1}{4} )$ cancel this out because it gives you one

But, keep: $\frac{4}{1} (-2)$ because it gives you the answer

$v = 8$

Good luck on your assignment
and enjoy your day

~ $MeIsKaitlyn:)$

5 0

3 years ago

Use the image

My name is Ann [436]

Well you multiply the -4 to the 9 using and you will get -36 then you divide by -6 and you will get 6 simple as that

8 0

3 years ago

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This is confusing please help

stira [4]

Step-by-step explanation:

since we are using Pythagoras

c² = a² + b²

with c being the Hypotenuse (the baseline opposite of the 90° angle),

you want to get the expression

y² = 3² + 3²

so, you pick the ² and put it next to the y left of the "=" sign.

and to the right of the "=" sign you put 3, ², +, 3, ²

3 0

2 years ago