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3 years ago

9/5C + 32 =59 I'm stuck on how to do this .. please help

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

8 0

Answer:

C= 15

Step-by-step explanation:

$\frac{9}{5} C + 32 = 59$

subtracting 32 from both sides

$\frac{9}{5}C = 59 -32$

$\frac{9}{5} C = 27$

Dividing both sides by 9/ 5

$C = 27 \times \frac{5}{9}$

$C = 3 \times 5$

$C = 15$

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9514 1404 393

Answer:

common denominator: (x² -4)
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Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

a² -b² = (a -b)(a +b)

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

$\dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}$

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