All categories

3 years ago

Evaluate the expression when a= -3 and C = 6 8c - a

Mathematics

2 answers:

Sav [38]3 years ago

8 0

Answer:

Step-by-step explanation:

plug in

8(6)- (-3)

48-(-3)

expeople1 [14]3 years ago

6 0

51 is the answer soo ya

You might be interested in

Mo spends £15 on ingredients to make 40 cookies.

ahrayia [7]

Given :

Mo spends £15 on ingredients to make 40 cookies.

He sells all 40 cookies for 50p each.

To Find :

The Mo's percentage profit.

Solution :

We know, 1 £ = 66.09 p.

So, total income is :

T = 40 × 50 p

T = 2000 p

T = £2000/66.09

T = £30.26

So, total profit is, P = £( 30.26 - 15 ) = £15.26 .

Hence, this is the required solution.

8 0

3 years ago

What is the best way to learn mathematics easily??

emmasim [6.3K]

I would recommend going to school

Or get a tutor

Or ask your parents

4 0

3 years ago

Solve 1/2x + 3 > 2(x-5/2)

Likurg_2 [28]

Answer:

1/4x (8 x - 15)

Step-by-step explanation:

write the division as a fraction

1/2x + 3/2x (x - 5 ÷ 2)

factor out 1/2 from the expression.

1/2x(x + 3(x - 5 ÷ 2))

divide the numbers.

1/2x(x + 3(x - 2.5))

distribute 3 through the parentheses.

1/2x(x + 3x - 7.5)

collect like terms.

1/2x(4x - 7.5)

1/2x(4x - 15/2)

factor out 1/2 from the expression.

1/2 x 1/2 x (8 x - 15)

multiply the fractions

= 1/4 x (8x - 15)

or alternative form

= 0.25(8x - 15)

6 0

3 years ago

I don't understand plz help

Rasek [7]

Answer:

The equation that represent x, the height of the sign is;

$2a = 3x$

Step-by-step explanation:

Given that the area of the triangular yield is A square feet

and it has a base length of 3 feet.

also the height is represented by x;

$b = 3ft \\ h = x$

Recall that the area of a triangle can be written as;

$a = \frac{1}{2} bh$

substituting the given;

$a = \frac{1}{2} \times 3 \times x \\ a = \frac{3}{2} x \\ 2a = 3x$

Therefore, the equation that represent x, the height of the sign is;

$2a = 3x$

8 0

2 years ago

Read 2 more answers

A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a

Rashid [163]

Answer:

Length of original rectangle: 11 units.

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

$\text{Perimeter of new rectangle}=20$

Step-by-step explanation:

Let x represent width of the original rectangle.

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be $x+6$ .

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be $x-2$ .

The length of new rectangle would be $x+6-4=x+2$ .

The area of new rectangle would be $(x+2)(x-2)$ .

Now we will equate area of new rectangle with 21 and solve for x as:

$(x+2)(x-2)=21$

Applying difference of squares, we will get:

$x^2-2^2=21$

$x^2-4=21$

$x^2-4+4=21+4$

$x^2=25$

Since width cannot be negative, so we will take positive square root of both sides.

$\sqrt{x^2}=\sqrt{25}$

$x=5$

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be $x+6\Rightarrow x+5=11$ .

Therefore, the length of original rectangle is 11 units.

$\text{Area of original rectangle}=5\times 11$

$\text{Area of original rectangle}=55$

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

We know that perimeter of rectangle is two times the sum of length and width.

$\text{Perimeter of new rectangle}=2((x+2)+(x-2))$

$\text{Perimeter of new rectangle}=2((5+2)+(5-2))$

$\text{Perimeter of new rectangle}=2(7+3)$

$\text{Perimeter of new rectangle}=2(10)$

$\text{Perimeter of new rectangle}=20$

Therefore, the perimeter of the new rectangle is 20 units.

7 0

3 years ago

Evaluate the expression when a= -3 and C = 6 8c - a​

Evaluate the expression when a= -3 and C = 6 8c - a