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2 years ago

9

If y varies directly as x, and y = 25 when x = 5, find y when x = 25.

2 answers:

s344n2d4d5 [400]2 years ago

8 0

It would be 125 so A

dezoksy [38]2 years ago

5 0

$\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ \rule{31em}{0.25pt}\\\\ \textit{we also know that } \begin{cases} y=25\\ x=5 \end{cases}\implies 25=k5\implies \cfrac{25}{5}=k \\[2em] 5=k\hspace{20em}\boxed{y=5x} \\[2em] \textit{when x = 25, what is \underline{y}?}\qquad y=5(25)\implies y=125$

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ella [17]

Answer: 24

Step-by-step explanation:

Number of marbles in jar = 32

Let blue marbles be represented by b.

Since there are three times as many green marbles as blue. This means that green will be = 3 × b = 3b

We then add them together. This will be:

3b + b = 32

4b = 32

b = 32/4

b = 8

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Since green is 3× blue. Therefore,

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7 0

2 years ago

Find two consecutive intergers whose sum is -29

boyakko [2]

-29= x + (x + 1)
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2 years ago

a fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closest to

gregori [183]

Answer:

The volume of the water in the fishbowl is equal to

$(682\frac{2}{3})\pi\ in^{3}$ or $2,144.6\ in^{3}$

Step-by-step explanation:

we know that

The volume of the sphere (a fishbowl) is equal to

$V=\frac{4}{3}\pi r^{3}$

In this problem we have

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substitute

$V=\frac{4}{3}\pi (8^{3})=\frac{2,048}{3}\pi\ in^{3}$

convert to mixed number

$\frac{2,048}{3}\pi\ in^{3}=\pi (\frac{2,046}{3}+\frac{2}{3})=(682\frac{2}{3})\pi\ in^{3}$

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3 years ago

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xenn [34]

Y = 5 - 4x

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3 years ago

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lina2011 [118]

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then multiply 2 and 12 to get 1/2(36)
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2 years ago

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