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The variance of a distribution is the square of the standard deviation
The variance of the data is 2.2
<h3>How to calculate the variance</h3>
Start by calculating the expected value using:

So, we have:

This gives

Next, calculate E(x^2) using:

So, we have:


The variance is then calculated as:

So, we have:


Approximate

Hence, the variance of the data is 2.2
Read more about variance at:
brainly.com/question/15858152
Answer:
Step-by-step explanation:
Here is the set up:
Let T = total deposit
T = (231.09) + 987.67+ 9.00 + 45.00 + 80.00 + 3.50 + 2.50 + 0.90 + 0.64
Take it from here.