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Setler [38]
3 years ago
14

A tree initially measured 18 feet tall. Over the next 312 years, it grew to a final height of 3512 feet. During those 312 years,

what was the average yearly growth rate of the height of the tree?
Mathematics
1 answer:
Leni [432]3 years ago
8 0

Answer:

Average growth= 11.20 feet

Step-by-step explanation:

<u>First, we need to calculate the total growth during those 312 years:</u>

<u></u>

Total growth= 3,512 - 18

Total growth= 3,494 feet

<u>Now, the average growth:</u>

<u>Average growth= total growth / number of years</u>

Average growth= 3,494 / 312

Average growth= 11.20 feet

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Step-by-step explanation:

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180-65=155

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Tyler bought 3 7/16 pounds of oranges. Write this amount using a decimal.
Whitepunk [10]
3(7/16) in your calculator should do it
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Can someone help me and explain step by step
Shkiper50 [21]

Answer:  5) r = 5, 8th term = -78,125

               6) r = 5, 8th term = -312,500

               7) r = 5, {1, 5, 25, 125, 625}

               8) r = 5, {-4, -20, -100, -500, -2500}

<u>Step-by-step explanation:</u>

The explicit formula of a geometric sequence is: a_n=a_1\cdot r^{n-1}, where;

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5)\ a_n=-5^{n-1}\\.\qquad =-1\cdot 5^{n-1}\quad \rightarrow \quad a_1=-1\ and\ r=5\\\\a_8=-5^{8-1}\\.\quad =-5^7\\.\quad =-78,125\\\\\\6)\ a_n=-4\cdot 5^{n-1}\quad \rightarrow \quad a_1=-4\ and\ r=5\\\\a_8=-4\cdot 5^{8-1}\\.\quad =-4\cdot 78,125\\.\quad =-312,500

7)\ a_1=1\ and\ r=5\\.\quad a_2=1\cdot 5=\boxed{5}\\.\quad a_3=5\cdot 5=\boxed{25}\\.\quad a_4=25\cdot 5=\boxed{125}\\.\quad a_5=125\cdot 5=\boxed{625}\\\\\\\\8)\ a_1=-4\ and\ r=5\\.\quad a_2=-4\cdot 5=\boxed{-20}\\.\quad a_3=-20\cdot 5=\boxed{-100}\\.\quad a_4=-100\cdot 5=\boxed{-500}\\.\quad a_5=-500\cdot 5=\boxed{-2500}\\\\\\

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3 years ago
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Answer:

y = 2x-4

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Divide each side by 4

8x/4 -16/4 = 4y/4

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