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Setler [38]
3 years ago
14

A tree initially measured 18 feet tall. Over the next 312 years, it grew to a final height of 3512 feet. During those 312 years,

what was the average yearly growth rate of the height of the tree?
Mathematics
1 answer:
Leni [432]3 years ago
8 0

Answer:

Average growth= 11.20 feet

Step-by-step explanation:

<u>First, we need to calculate the total growth during those 312 years:</u>

<u></u>

Total growth= 3,512 - 18

Total growth= 3,494 feet

<u>Now, the average growth:</u>

<u>Average growth= total growth / number of years</u>

Average growth= 3,494 / 312

Average growth= 11.20 feet

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a_{n+1}=a_n+d

This is the part that's probably easier for you to remember. The explicit formula is easily derived from this definition. Since a_{n+1}=a_n+d, this means that a_n=a_{n-1}+d, so you plug this into the recursive formula and end up with 

a_{n+1}=(a_{n-1}+d)+d=a_{n-1}+2d

You can continue in this pattern, since every term in the sequence follows this rule:

a_{n+1}=a_{n-1}+2d
a_{n+1}=(a_{n-2}+d)+2d
a_{n+1}=a_{n-2}+3d
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and so on. You start to notice a pattern: the subscript of the earlier term in the sequence (on the right side) and the coefficient of the common difference always add up to n+1. You have, for example, (n-2)+3=n+1 in the third equation above.

Continuing this pattern, you can write the formula in terms of a known number in the sequence, typically the first one a_1. In order for the pattern mentioned above to hold, you would end up with

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