Answer:
15
Step-by-step explanation:
12 x 0.25= 3
12+3=15
The standard algorithm<span> of multiplication is based on the principle that you already know: multiplying in parts (partial products): simply multiply ones and tens separately, and add.
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We are given a problem that can be solved using a system of linear equations. Let A, be the number of adults, and S the number of students. Since there are in total 142 people and there were two days, this means that the sum of the number of adults and the number of students must be 284, which can be written mathematically as follows:

This is our first equation. The second equation is found using the total sales of $1948. Since the ticket per adult is $8 and per student is $5, we have the following equations:

To solve this equation we will solve for A in equation (1), by subtracting S to both sides;

Now we will replace this value in equation (2):

Now we will apply the distributive property:

Addins like terms:

Subtracting 2272 to both sides;

Dividing both sides by -3:

Now we replace this value in equation (1), where we have already solved for A:

Therefore, there were sold 108 student tickets and 140 adult tickets.
21. Find the unit rate ($ per fl oz). Compare the two prices.
22. Multiply 2 3/5 by 7, and 5 3/4 by 4. Add those together and get the answer.
Hope that helps!
I am not sure if what I am about to explain is correct but I hope it is somewhere along the correct path
To solve the problem use the following steps below....
Step 1: Take your numbers and place them in parentheses
(4-1/6)
Step 2: Turn your whole number,4, into a fraction
6/6=1
6/6x4=24/6
Step 3: Place your new fraction back into the problem
(24/6-1/6)
Step 4: Use the operation,subtraction, and minus 1/6 from 24/6
(23/6)
24/6 minus 1/6=23/6
Step 5(is optional): Turn 23/6 into a mixed fraction by dividing 23 by 6
23<span>÷6= 3 5/6
Step 6(is optional): put your answer into a final statement
(4-1/6)=23/6=3 5/6
Answer: 3 5/6
I hope this helps and I apologize in advance if any false information was given.
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