Answer:
The probability that our guess is correct = 0.857.
Step-by-step explanation:
The given question is based on A Conditional Probability with Biased Coins.
Given data:
P(Head | A) = 0.1
P(Head | B) = 0.6
<u>By using Bayes' theorem:</u>
We know that P(B) = 0.5 = P(A), because coins A and B are equally likely to be picked.
Now,
P(Head) = P(A) × P(head | A) + P(B) × P(Head | B)
By putting the value, we get
P(Head) = 0.5 × 0.1 + 0.5 × 0.6
P(Head) = 0.35
Now put this value in , we get
Similarly.
Hence, the probability that our guess is correct = 0.857.
Answer:
I believe the answer is 1/5 please tell me if I am wrong and I am truly sorry if I am
Step-by-step explanation:
The answer is 11/36
2/12 chance of rolling fours
because there are 2 sides containing a four on both dice combined and 12 sides in total.
Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.
I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.
1/6 * 1/6 = 1/36 chance to roll double of ones
And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:
1/36 * 5 = 5/36
So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:
5/36 + 2/12 =
5/36 + 6/36 =
11/36
It’s B because it equals -8 when simplified which is a rational number
