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matrenka [14]
3 years ago
10

Order the following numbers from least to greatest

Mathematics
2 answers:
ryzh [129]3 years ago
5 0

Answer:

-43, -29, 29, 43

\\Step-by-step explanation:

otez555 [7]3 years ago
5 0
The answer would be, -43,-29, 29, 43
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12 fewer means to subtract 12 so you would have h-12
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Is-0.62 greater than or less than -6/7
NNADVOKAT [17]
-6/7 = -0.85
-31/50 = -0.62
So -0.62 is greater than -0.85
-0.62 < -0.85
Because the bigger the fraction is the less it actually is and I think the same goes for decimals . Hope I helped
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Does anyone know how to solve this? If so pls let me know
Andre45 [30]
Yes the value of X is 12.53 :)

Pythagorean theorem.

11•11=121+6•6=36=157
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Find the sum of the first 10 terms for the sequence {21, 63, 189, . . . }.
antiseptic1488 [7]
The sum of n terms of a geometric sequence with first term "a" and common ratio "r" is given by
S_{n}=a\dfrac{r^{n}-1}{r-1}
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S_{10}=21\cdot \dfrac{3^{10}-1}{3-1}=620004

The appropriate choice is the 2nd one:
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4 years ago
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Different sizes of ribbon need to be cut to go around various shapes for a craft project.
Dima020 [189]

You have five numbers \sqrt{6},\ 2\dfrac{1}{2},\ -\sqrt{1},\ \dfrac{7}{2}, \ 3.\overline{3}.

Among them there is one negative number -\sqrt{1}, this number is smallest.

Note that

(\sqrt{6} )^2=6 \text{ and } \left(2\dfrac{1}{2}\right)^2=(2.5)^2=6.25.

Since 6.25>6, then

2\dfrac{1}{2}>\sqrt{6}

and these numbers are less than 3

Note that

\dfrac{7}{2}=3.5 \text{ and } 3.\overline{3}=3.333333....,

then 3.3333333... and these numbers are greater than 3.

Therefore, the correct order from the smallest to the greatest is:

-\sqrt{1}, \quad \sqrt{6},\quad 2\dfrac{1}{2},\quad 3.\overline{3}, \quad \dfrac{7}{2}.

3 0
3 years ago
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