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Alexandra [31]
3 years ago
12

How do you solve 5h>4

Mathematics
1 answer:
blagie [28]3 years ago
8 0

Answer:

any number equal or greater than 1

Step-by-step explanation:

5 time what is bigger the 4

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Evaluate the expression 81-8^2
Tpy6a [65]

Answer:

17

Step-by-step explanation:

Do the exponent first, then subratct it to 81

7 0
3 years ago
Which of the following is equivalent to<br> 36^-1/2
guapka [62]

Step-by-step explanation:

{36}^{ -  \frac{1}{2} }  \\  \\  =  \frac{1}{ {36}^{  \frac{1}{2} } }  \\  \\  =   \frac{1}{ {( {6)}}^{  2 \times \frac{1}{2} } }  \\  \\  =  \frac{1}{ {{6}}}

3 0
4 years ago
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

7 0
3 years ago
Given the following equations, find a formula for g(ſ(x))<br> g(x) = -X-7<br> F(x)=-8x^2-5
andre [41]
Answer: 8x^2 -2

Explanation:
Think about it like your pluging in a number for x, like g(1) or g(x+1), but plug in the equation for f(x)
g(f(x))= -(-8x^2 -5) -7
=8x^2 +5 -7
=8x^2 -2
5 0
3 years ago
Which of the following situations can be modeled by the expression 5 - (-3)?
Sedaia [141]

Answer:the first option

Step-by-step explanation:

8 0
2 years ago
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