I agree with the 14x all right, but the remainder of the other part is 178. I'm going to recheck my answer. I'm not confident about using synthetic division for this question. It is 57 years since I did something like this. If I was more confident, I would list the results of synthetic division because it is much easier to show than long division. I'm saying the answer should be 14x + 178.
3x greater than or equal to 20
3x = 20
X= 7 games for the pass to be better
3(7)=21
Answer:
Sum of the first 15 terms = -405
Step-by-step explanation:
a + 3d = -15 (1)
a + 8d = -30 (2)
Where,
a = first term
d = common difference
n = number of terms
Subtract (1) from (1)
8d - 3d = -30 - (-15)
5d = -30 + 15
5d = -15
d = -15/5
= -3
d = -3
Substitute d = -3 into (1)
a + 3d = -15
a + 3(-3) = -15
a - 9 = -15
a = -15 + 9
a = -6
Sum of the first 15 terms
S = n/2[2a + (n − 1) × d]
= 15/2 {2×-6 + (15-1)-3}
= 7.5{-12 + (14)-3}
= 7.5{ -12 - 42}
= 7.5{-54}
= -405
Sum of the first 15 terms = -405
Answer:
11 is 150
12 is 168 lectures and 70 professers
Step-by-step explanation:
Correct answer is 4:13 am
