the three numbers are 49,56 and 63.
Let us use x as the cost before Chet would apply a $25 gift certificate. Based on the problem, we can see that the original cost of the product cannot be more than 75 which means that it can be equal to 75 or less than 75. We can actually express the inequality as x< or = 75 since we are looking for the cost before Chet applied the $25 gift certificate. This means that we do not need to add in the 25 yet since the question asks for the cost before the application of the discount. - Credits, <span>Taskmasters and Hegans</span>
Assuming LCD means Lowest Common Denominator
Assuming by "and" you mean adding the two
Well, you go by the multiples of 7;
7, 14, 21, 28, 35, 42, 49, 56, 63,<u> 70</u>
Multiples of 10;
10, 20, 30, 40, 50, 60, <u>70</u>, 80, 90, 100
Straight away you can see the lowest common multiple is 70,
Now to go about adding them,
2/7 * 10 (both sides) , 20/70
9/10 * 7 (both sides) , 63/70
Then you add the two; 20/70 + 63/70 - now we can add them because they share the same denominator
20/70 + 63/70 = 83/70 = 1 whole 13/70 (simplified)
<u>The LCD is 70
Quick tip, </u>to find a common multiple (not necessarily the lowest) multiply the two denominators.
Triangle B can be proven congruent
Answer:
The anwser is number 4
Step-by-step explanation:
