2 years ago

Please help me ASAP and please show me how you did it.

Mathematics

1 answer:

Nadusha1986 [10]2 years ago

8 0

Answer:

2. Find m

sin m˚ = 2/5

sin^-1 (2/5) = m˚

m˚ = 23.57˚

3. Sine law

$\frac{8}{sin103}=\frac{5}{sin\alpha }$

$\frac{5sin103}{8}=sin^{-1}(0.608)=37.5$

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Given directed line segment PR below, find the coordinates of Q on PR

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Answer:

$(\frac{4}{3},-3)$

Step-by-step explanation:

The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at ( $x_1,y_1$ ) and B( $x_2,y_2$ ) is given by the formula:

$x=\frac{a}{a+b}(x_2-x_1)+x_1\\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1$

From the graph, the location of the point is P(2, 5), R(1, -7). Let point Q be (x, y) which divides PR in ratio 2:1. Coordinates of point Q is at:

$x=\frac{a}{a+b}(x_2-x_1)+x_1=\frac{2}{2+1}(1-2)+2=\frac{2}{3}(-1)+2=\frac{4}{3} \\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1=\frac{2}{2+1}(-7-5)+5= \frac{2}{3}(-12)+5=-3$