Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.
Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w. Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:
1/16 CCWW (lethal)
2/16 CCWw (white)
2/16 CcWW (lethal)
4/16 CcWw (white)
1/16 CCww (normal)
2/16 Ccww (normal)
2/16 ccWw (albino)
1/16 ccWW (lethal)
1/16 ccww (albino)
Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.
Answer:
Example 1 Find the inverse transform of each of the following.
F
(
s
)
=
6
s
−
1
s
−
8
+
4
s
−
3
H
(
s
)
=
19
s
+
2
−
1
3
s
−
5
+
7
s
5
F
(
s
)
=
6
s
s
2
+
25
+
3
s
2
+
25
G
(
s
)
=
8
3
s
2
+
12
+
3
s
2
−
49
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Answer:
I think its $1 every 4 oz
Step-by-step explanation:
Basing this off that 4 * 4 is 16
If two angles are equal, then the two angles are obtuse.
Answer:
1. A, B, C, E
2.Im not sure I think A
hope this helps
have a good day :)
Step-by-step explanation:
