Ms. Jackson wrote the expression shown on the board and asked her class to find an equivalent expression.
1 answer:
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Answer:
0.7931 = 79.31% probability that a truck drives between 43 and 141 miles in a day.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the probability that a truck drives between 43 and 141 miles in a day.
This is the pvalue of Z when X = 141 subtracted by the pvalue of Z when X = 43. So
X = 141
has a pvalue of 0.8599
X = 43
has a pvalue of 0.0668
0.8599 - 0.0668 = 0.7931
0.7931 = 79.31% probability that a truck drives between 43 and 141 miles in a day.