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3 years ago

What is 3 and 1 tenth as a desimal

Mathematics

1 answer:

Bess [88]3 years ago

5 0

Representing 3 and one tenth as decimal by 3.1

<u>Step-by-step explanation:</u>

Here 3 is the whole number.

1 tenth is nothing but $\frac{1}{10}$ .

$\frac{1}{10}$ = 0.1

When we write numerals with tenths using the decimals we can use a decimal point also the tenths positioned to the right of the decimal point. The tenth place is denoted as immediately right to the decimal point.

So it is represented as 3.1.

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In the data set below, which of these points is most likely and outlier?

shusha [124]

<h2>Answer:</h2>

Option: D is the correct answer.

D. (2,54)

<h2>Step-by-step explanation:</h2>

We know that an outlier of a data set is the value that stands out of the rest of the data point i.e. either it is a too high value or a too low value as compared to other data points.

Here we are given a set of data points as:

(2,54)

(4,7)

(6, 9)

(8,12)

(10,15)

Hence, we see that the output values i.e. 7 in (4,7) ; 9 in (6,9) ; 12 in (8,12) and 15 in (10,15) are closely related.

Hence, the data point that is an outlier is:

(2,54)

(As 54 is a much high value as compared to other)

5 0

3 years ago

A concert hall has seven sections. Each section has twenty-three rows. Each row has fourteen seats. If the theater sells out for

gayaneshka [121]

If the theater sells out, 2254 people would have attended. With each ticket being 20 dollars, $45,080 would have been collected at the box office

7 0

3 years ago

HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work

Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) $8+6x^4$

here we can see, both numbers are divisible by 2, so taking 2 common

$=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)$

It cannot be further simplified because both number donot have same bases.

3. $4n^9 + 12 n$

We can take 4n common

$=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)$

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. $12n^5 + 16n^3$

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

$4n^3( 3n^2 + 4)$

9. $5k^2 - 40k+10$

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

$=5(k^2 - 8k + 2)$

11. $-60 + 60n^2 +50n^3$

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

$=10(-6 + 6n^2 +5n^3)$

13. $-36n^3 -12n-28$

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

$=-4(9n^3 + 3n +7)$

15. $63n^3+81n+18$

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

$=9(7n^3 + 9n + 2)$