Answer:
![\left[\begin{array}{cc}2&8\\5&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%268%5C%5C5%261%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The <em>transpose of a matrix </em>
is one where you swap the column and row index for every entry of some original matrix 
. Let's go through our first matrix row by row and swap the indices to construct this new matrix. Note that entries with the same index for row and column will stay fixed. Here I'll use the notation 
and 
to refer to the entry in the i-th row and the j-th column of the matrices 
and 
respectively:
Constructing the matrix from those entries gives us
![P^T=\left[\begin{array}{cc}2&8\\5&1\end{array}\right]](https://tex.z-dn.net/?f=P%5ET%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%268%5C%5C5%261%5Cend%7Barray%7D%5Cright%5D)
which is option a. from the list.
Another interesting quality of the transpose is that we can geometrically represent it as a reflection over the line traced out by all of the entries where the row and column index are equal. In this example, reflecting over the line traced from 2 to 1 gives us our transpose. For another example of this, see the attached image!
To find the answer of the first one, plug in numbers for x, and see if they make the inequality true. Like, 5, 6, and 7.
For the second one, add 13 to both sides. The answer is 21.
Answer:
good luckgood luckgood luckgood luck
Step-by-step explanation:
good luckgood luckgood luckgood luck
Answer:
66
Step-by-step explanation:
I have a lot to do so there won't be a step by step
Answer:
Cameron need to mow 4 lawns.
Step-by-step explanation:
Cameron needs 11$ for some new toys.
But he charges 3$ to mow a lawn.
So, he needs to mow 11/3= 3.66... lawns
The number of lawns can not be decimal. So, let's round to next whole number as 4.
