Answer:
<u><em>ΔEAB ≅ΔFCD</em></u>
Step-by-step explanation:
As ABCD is a parallelogram opposite sides are equal s AE ≅CF ,also AB≅ DC . Both E and F bisect the opposite lines in equal halves.
The parallelogram has a property that its opposite angles are equal . Therefore ∠c≅∠a, ∠d≅∠b
Using the SAA≅SAA postulate we conclude that ΔEAB ≅ΔFCD
The correct answer is "B". 'Two show the congruence of two triangles, only two angles at most need to be shown.' If you know 2 angles as congruent or equal, you can figure out the third one. It will always be the same. All of a triangles' angles' add up to 180 degrees.
I hope this helped you!
Brainliest answer is always appreciated!
the one where they are diagonal from one another
The answer is the first one. move 5 1/2 units right and 1 unit down.