Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y)) ∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y)) ∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z) ∀x ∃z> V (x,y,z))
Answer:
Part 1)
Part 2)
Part 3)
Part 4)
Step-by-step explanation:
step 1
Find the length side c
Applying the Pythagoras Theorem
substitute the given values
step 2
Fin the measure of angle B
we know that
In the right triangle
substitute the given values
step 3
Find the measure of angle A
we know that
The measure of interior angles in a triangle must be equal to 180 degrees
so
∠A+∠B+∠C=180°
Remember that in a right triangle the measure of angle C is 90 degrees
we have
substitute