let's recall that the graph of a function passes the "vertical line test", however, that's not guarantee that its inverse will also be a function.
A function that has an inverse expression that is also a function, must be a one-to-one function, and thus it must not only pass the vertical line test, but also the horizontal line test.
Check the picture below, the left-side shows the function looping through up and down, it passes the vertical line test, in green, but it doesn't pass the horizontal line test.
now, check the picture on the right-side, if we just restrict its domain to be squeezed to only between [0 , π], it passes the horizontal line test, and thus with that constraint in place, it's a one-to-one function and thus its inverse is also a function, with that constraint in place, or namely with that constraint, cos(x) and cos⁻¹(x) are both functions.
Answer
Find out the how long are the two line segments together answer in cm .
To prove
As given
i am measurng two line segments the first line is 30centimeter long.
The second line segment is 500 millimeter .
As
1 millimeter = 0.1 centimeter
Now convert 500 millimeter into centimeter .
500 millimeter = 500 × 0.1 centimeter
= 50 centimeter
Thus second line segment be 50 centimeter long .
Total length of two line segments = 30 + 50
= 80 cm
Therefore the 80 cm long are the two line segments together answer in cm .
Answer:
12m
Step-by-step explanation
If the height of the ball after x seconds be modelled by the equation
h(x)=−(x−2)² +16
The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0
To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;
h(0) = -(-0-2)²+16.
h(0) = -(-2)²+16
h(0) = -4+16
h(0) = 12
The height of the ball at the time the ball is thrown is 12m
I think the answer is 17.5 years
4/9 divided by 2/3 divided by 5/6 = 4/5
when you divided by two fractions, you can flip the denominator and numerator and then mutiply
