Ask question

Ask question

All categories

3 years ago

15

WILL NAME brainliest

2 answers:

kolezko [41]3 years ago

7 0

Answer:

$x=13$

Step-by-step explanation:

By the definition of an angle bisector, we have that $8x-23=5x+16$ .

We can add $23$ to both sides to get $8x=5x+39$ .

We can then subtract $5x$ from both sides to get $3x=39$ .

We can finally divide both sides by $3$ to get $\boxed{x=13}$

blagie [28]3 years ago

6 0

The answer is x = 13

You might be interested in

Find the measures of the interior angles.

Svetradugi [14.3K]

Answer:

45 degrees.

Step-by-step explanation:

All interior angles in a triangle add up to 180 degrees.

We can form an equation: x+x+65+25=180

2x+90=180

2x=90

x=45.

7 0

3 years ago

Which expression is equivalent to 364ab7c9?

charle [14.2K]

What do you mean is there an image

6 0

3 years ago

Please help me with this soon much appreciated.

NeX [460]

Answer:

1 : 2

Step-by-step explanation:

this is a 30-60-90 triangle which is a special right triangle. the ratio of the sides is x: x*sqrt(3): 2x, in the order short leg: long leg: hypotenuse. so the ratio of the short leg to the hypotenuse is x:2x or 1:2

8 0

2 years ago

Select the correct answer.<br> Find the value of g(7) for the function below.<br> g(x) = zur

ale4655 [162]

Answer:

B

Step-by-step explanation:

To evaluate g(7) substitute x = 7 into g(x) , that is

g(7) = $\frac{7}{8}$ × 7 - $\frac{1}{2}$

= $\frac{49}{8}$ - $\frac{4}{8}$

= $\frac{45}{8}$ → B

5 0

3 years ago

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

3 years ago