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Elan Coil [88]
3 years ago
5

Can someone help me with this??? I’ll give brainliest!!!

Mathematics
1 answer:
Kitty [74]3 years ago
8 0
I can’t see the picture please make it clear
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This is the question...plz hurry..thx
svetlana [45]

Answer:

20x-21y+14

Step-by-step explanation:

1/5(100x-105y+70)

20x-21y+14

6 0
3 years ago
Plsss help meeeeeee I would really appreciate it I would be really happy if u help meeee
Mashcka [7]

<em>the \: answer \: is \: 22.4 \: cm \\ please \: see \: the \: attached \: picture \\ for \: full \: solution \\ hope \: it \: helps</em>

4 0
3 years ago
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What is the probability of rolling a 6-sided die and getting a 4 number divisible by 3?
Illusion [34]

Answer: Hello mate!

In a fair die all the number have the same probability; 1/6

The probability of getting a 4 is the sides with the number 4 divided by the total amount of numbers in the dice, this is 1 divided by, the probability is 1/6

The probability o getting a number divisible by 3 is the number of numbers that are divisible by 3 divided by the total amount of numbers in the dice:

The numbers divisible by 3 are 3 and 6, and in the dice, there are 6 numbers in total, so the probability is 2/6 = 1/3

4 0
3 years ago
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Divide. (-1/5) divided by (-4/5) what is the quotient
worty [1.4K]

Answer:

I believe it's 1/4

Step-by-step explanation:

4 0
3 years ago
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An artificial lake is in the shape of a rectangle and has an area of 9/20 square mile the width of the lake is 1/5 the length of
DIA [1.3K]
Answer:  The dimensions are:   " 1.5 mi.  ×  ³⁄₁₀  mi. " .
_______________________________________________
             { length = 1.5 mi. ;  width =  ³⁄₁₀  mi. } .
________________________________________________
Explanation:
___________________________________________
Area of a rectangle:

A = L * w ; 

in which:  A = Area = (9/20) mi.² ,
                L = Length = ?
                w = width = (1/5)*L = (L/5) = ?
________________________________________
  A = L * w ;  we want to find the dimensions; that is, the values for
                         "Length (L)"  and "width (w)" ; 
_______________________________________
Plug in our given values:
_______________________________________
 (9/20) mi.² = L * (L/5) ;  in which: "w = L/5" ; 
 
     → (9/20) = (L/1) * (L/5) = (L*L)/(1*5) = L² / 5 ;
   
          ↔  L² / 5  = 9/20 ;
 
            →  (L² * ? / 5 * ?) = 9/20 ?    

                →     20÷5 = 4 ;  so; L² *4 = 9 ;
 
                   ↔    4 L² = 9 ; 
 
                   →  Divide EACH side of the equation by "4" ;
           
                   →   (4 L²) / 4 = 9/4 ;
______________________________________
           to get:  →  L² = 9/4 ; 
 Take the POSITIVE square root of each side of the equation; to isolate "L" on one side of the equation; and to solve for "L" ;
___________________________________________          
 
     →   ⁺√(L²)   =   ⁺√(9/4) ;

    →   L  =  (√9) / (√4) ; 

    →  L = 3/2 ; 

    → w = L/5 = (3/2) ÷ 5 = 3/2 ÷ (5/1) = (3/2) * (1/5) = (3*1)/(2*5) = 3/10;
________________________________________________________
Let us check our answers:
_______________________________________
(3/2 mi.) * (3/10 mi.) =? (9/20) mi.² ??

→ (3/2)mi. * (3/10)mi.  =  (3*3)/(2*10) mi.² = 9/20 mi.² ! Yes!
______________________________________________________
So the dimensions are: 

Length = (3/2) mi. ;  write as: 1.5 mi.

width = ³⁄₁₀ mi.
___________________________________________________
or; write as:  " 1.5 mi.  ×  ³⁄₁₀ mi. " .
___________________________________________________
7 0
3 years ago
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