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3 years ago

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A cylinder’s volume must be 850 cubic feet while the radius of the cylinder cannot exceed 6 feet. What is the smallest possible

height for the cylinder? A 7.5 ft B 23.6 ft C 141.7 ft

1 answer:

Neporo4naja [7]3 years ago

6 0

I think it's B. not sure though u should wait. till someone else answer to see if I am right

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svetoff [14.1K]

Answer:

A: 37/41

Step-by-step explanation:

<u>We can observe that:</u>

The difference of the second and third numbers is equal to 17
The difference of the first and fourth numbers is equal to 13

<u>Therefore the missing pair will be:</u>

20+17 = 37 and 28 + 13 = 41

Correct choice is A

3 0

3 years ago

Let x △ y be defined by x △ y=x−5y. What is the value of 3 △ (−4)

TEA [102]

$x\Delta y=x-5y\\\\3\Delta(-4)\qquad\text{put the values x = 3 and y = -4 to the expression x - 5y}:\\\\3\Delta(-4)=3-5(-4)=3+20=23$

5 0

3 years ago

Can anyone help me with this? thank you

wel

"MIDDLE OF THE NIGHT"

I summoned you, please come to me

Don't bury thoughts that you really want

I fill you up, drink from my cup

Within me lies what you really want

Come, lay me down

'Cause you know this

'Cause you know this sound

In the middle of the night

In the middle of the night

Just call my name

I'm yours to tame

In the middle of the night

In the middle of the night

I'm wide awake

I crave your taste all night long

'Til morning comes

I'm getting what is mine

You gon' get yours, oh no, ooh

In the middle of the night

In the middle of the night, oh

These burning flames, these crashing waves

Wash over me like a hurricane

I captivate, you're hypnotized

Feel powerful, but it's me again

Come, lay me down

'Cause I know this

'Cause I know this sound

In the middle of the night

In the middle of the night

Just call my name

I'm yours to tame

In the middle of the night

In the middle of the night

I'm wide awake

I crave your taste all night long

'Til morning comes

I'm getting what is mine

You gon' get yours, oh no, ooh

In the middle of the night

In the middle of the night, oh

Just call on me, ah

Just call my name

Like you mean it, ah

In the middle of the night

In the middle of the night

Just call my name

I'm yours to tame

In the middle of the night

In the middle of the night

I'm wide awake

I crave your taste all night long

'Til morning comes

I'm getting what is mine

You gon' get yours, oh

In the middle of the night

In the middle of the night, o

Step-by-step explanation:

5 0

2 years ago

Which point lies on the graph of Y= 4x-4<br> 1.(0,4)<br> 2.(0,-4)<br> 3.(-4,0)<br> 4.(4,0)

statuscvo [17]

Answer:

<h2>2. (0, -4)</h2>

Step-by-step explanation:

$y=4x-4\\\\\text{Substitute the coordinates of each points to the equation}\\\text{and check the equality.}\\\\1.\ (0,\ 4)\to x=0,\ y=4\\\\4=4(0)-4\\4=0-4\\4=-4\qquad\bold{FALSE}\\\\2.\ (0,\ -4)\to x=0,\ y=-4\\\\-4=4(0)-4\\-4=0-4\\-4=-4\qquad\bold{TRUE}\\\\3.\ (-4,\ 0)\to x=-4,\ y=0\\\\0=4(-4)-4\\0=-16-4\\0=-20\qquad\bold{FALSE}\\\\4.\ (4,\ 0)\to x=4,\ y=0\\\\0=4(4)-4\\0=16-4\\0=12\qquad\bold{FALSE}$

5 0

3 years ago

34% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a

finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

10 student are sampled, so $n = 10$

34% of college students say they use credit cards because of the rewards program, so $\pi = 0.34$

(a) exactly two

This is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than two

This is $P(X > 2)$ .

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

$P(X \leq 2) + P(X > 2) = 1$

$P(X > 2) = 1 - P(X \leq 2)$

In which

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

So

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157$

$P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838$

$P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162$

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873$

$P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573$

$P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320$

$P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434$

$P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82$

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0

3 years ago