<h2>9.</h2><h3>Given</h3>
<h3>Find</h3>
- linear approximation to the volume when the radius increases 0.4 cm
<h3>Solution</h3>
The equation for volume of a sphere is
... V = (4/3)π·r³
Differentiating gives
... dV = 4π·r²·dr
Filling in the given numbers gives
... change in volume ≈ 4π·(15 cm)²·(0.4 cm)
... = 360π cm³ ≈ 1130.97 cm³ . . . . . . volume of layer 4mm thick
<h2>11.</h2><h3>Given</h3>
- an x by x by 2x cuboid with surface area 129.6 cm²
- rate of change of x is 0.01 cm/s
<h3>Find</h3>
<h3>Solution</h3>
The area is that of two cubes of dimension x joined together. The area of each such cube is 6x², but the two joined faces don't count in the external surface area. Thus the area of the cuboid is 10x².
The volume of the cuboid is that of two cubes joined, so is 2x³. Then the rate of change of volume is
... dV/dt = (d/dt)(2x³) = 6x²·dx/dt
We know x² = A/10, where A is the area of the cuboid, so the rate of change of volume is ...
... dV/dt = (6/10)A·dx/dt = 0.6·(129.6 cm²)(0.01 cm/s)
... dV/dt = 0.7776 cm³/s
First, you add up all the prices. 1.79 + 2.99 + 4.37 + 0.33 = 9.48. Then, you do 10.00 - 9.48 = 0.52 and that's your answer.
Answer:
m∠P=140°
Step-by-step explanation:
Given:
∠P and ∠Q are supplementary angles.
The measure of angle P is five less than four times the measure of angle Q.
To find m∠P
Solution:
The measure of angle P can be given as:
A) 
And
B) 
[Definition of supplementary angles]
Substituting equation A into B.
Solving for 
Using distribution:
Simplifying by combining like terms.
Adding 20 to both sides.
Dividing both sides by 5.
Substituting in equation B.
Subtracting both sides by 40.
Thus, we have:
m∠P=140° (Answer)
Answer:
what do u want help with
Step-by-step explanation:
Y=3
Simplify
Distribute
Combine like terms
Add 2y to both sides
Add 2 to both sides
Divide by 3 , both sides.
If u want me to write the numbers and all just reply
