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3 years ago

Help me please and thank you

Mathematics

1 answer:

UNO [17]3 years ago

4 0

The answer to the question is 64°

x° + 26°= 90°

x° = 64°

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What's the algebraic expression for the sum of v and 3

dangina [55]

The sum means addition
v + 3

6 0

3 years ago

Please help mee I don't understand this for some reasonnnn!!

Vesnalui [34]

Answer:

bivariate data

Scatter plot

positive assossiation

negitive assossiation

linear assocciation

nonlinear assocciaton

clustering

outlier

Step-by-step explanation:

7 0

2 years ago

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

Put $(x,y)=(1,1)$

$\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9$

This is true.

So, the point $(1,1)$ satisfies the equation $\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

So, point H is $(1,1)$ .

7 0

3 years ago

3.75<br>divided by 25<br>round off to the nearest rand

sattari [20]

Answer:

0.15 is the answer

Step-by-step explanation:

7 0

2 years ago

I will give BRAINLEST TO WHO ANSWER !!!!!

Snowcat [4.5K]

Answer:

a=7 b=24 c=25

Step-by-step explanation:

Leg a=7

Leg b=24

According to Pythagorean theorem: a^2+b^2=c^2

49+576=c^2

C^2=625

c=25

8 0

2 years ago

Read 2 more answers