Answer:
87.5%
Step-by-step explanation:
Complete question -
75% of the people who eat at Doug's Diner order fish and 90% of the people who order fish also order fries. Given that 80% of all people who eat at Doug's order fries, what is the probability that a randomly chosen customer orders fries without fish?
Solution
Given
People who order fish at the Doug's Diner = 75%
Out of this 75%, 90% also order fries which means that nearly 67.5% ordered fries with the fish.
Given that, 80% of people dining at Doug's Diner order fries
Then percentage or people who ordered only fires and no fish = 80% - 67.5% = 12.5%
The probability of customers who ordered fish = 100 - 12.5% = 87.5%
Answer:
72
Step-by-step explanation:
x/6 - 10 = 2
x/6 = 12 (add 10 to both sides)
x = 72 (multiply 6 to both sides)
I graphed it. First you choose a number that’s less than 29 and greater than 29 which I chose 0 and 100 but it didn’t let me show the whole picture
31=2y-5
Add 5 on both -5+5 which cancels out and 31+5 which is 36 and then divide 36 by 2 which equals to 18.
So y=18 hope this helped (':
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