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2 years ago

For the following right triangle, find the side length x, Round your answer to the nearest hundredth.

Mathematics

2 answers:

ladessa [460]2 years ago

8 0

You can search it on googlr

4vir4ik [10]2 years ago

3 0

Answer:

10.6. (3s.f.)

Step-by-step explanation:

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Solve this pls thank you

Nana76 [90]

Answer:21

Step-by-step explanation:9+10=21

5 0

2 years ago

The area of a triangle is 41 yd^2, with a base of 5 yards. What is the height, in yards?

Annette [7]

Answer:

I am pretty sure the answer would be A.

8 0

2 years ago

What is the argument of -5\sqrt{3}+ 5i?

Shtirlitz [24]

Answer:

150 degrees

Step-by-step explanation:

Graphing the complex number we see the angle terminates in the second quadrant. This means the argument, the angle, will be between 90 degrees and 180 degrees.

So if we create a right triangle with that point after graphing it. We see the height of that triangle is 5 because that is the imaginary part. The base of that triangle has length $5\sqrt{3}$ . The problem is this doesn't give us any part of the angle we want, but it does give us the complementary of the part of the angle that is in second quadrant.

Let's find the complementary angle.

So the opposite side of the complementary angle is 5.

The adjacent side of the complementary angle is $5\sqrt{3}$ .

$\tan(\theta)=\frac{5}{5\sqrt{3}}$

$\tan(\theta)=\frac{1}{\sqrt{3}}$

$\theta=\tan^{-1}(\frac{1}{\sqrt{3}})$

$\theta=30$

So 90-30=60.

The answer therefore 60+90=150.

4 0

2 years ago

Which strategy best explains how to solve this problem?

Rufina [12.5K]

This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number

In this case we have r=2 and a=1 so

a(n)=2^(n-1) so on the sixth week he will run:

a(6)=2^5=32

He will run 32 blocks by the end of the sixth week.

Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:

s(n)=a(1-r^n)/(1-r) where the variables have the same values so

s(n)=(1-2^n)/(1-2)

s(n)=2^n-1 so

s(6)=2^6-1

s(6)=64-1

s(6)=63 blocks

So he would run a total of 63 blocks in the six weeks.

4 0

2 years ago

Read 2 more answers

Compare the exponential functions f, g, and h which are shown below.

Nostrana [21]

Hello,
Please, see the detailed answer in the attached files.
Thanks.

5 0

2 years ago