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3 years ago

SOMEONE ANSWER QUICK!!

Mathematics

1 answer:

qaws [65]3 years ago

4 0

Answer:

3/4 of a pizza is left.

Step-by-step explanation:

4 pizzas minus (2 and 7/12 plus 2/3). Change 2/3 to 8/12 by multiplying the numerator and denominator by 4 to get both denominators the same. 4 pizzas minus (2 and 7/12 plus 8/12 or 2 and 15/12 or 3 and 3/12 or 3 and 1/4). Restated 4 pizzas minus 3and 1/4 pizzas 3/4 pizzas. 3/4 of a pizza is left.

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Need help will give brainliest easy math

natka813 [3]

Answer:

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Step-by-step explanation:

5 0

3 years ago

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A scientist performs an experiment to produce a compound by adding various amounts of a catalyst to a chemical reaction. Her dat

zhannawk [14.2K]

Answer: 21.69 g

Step-by-step explanation:

Find the amount of compound produced when 300 mg of catalyst is added

<u>Given:</u>

Equation: A = 0.06c + 3.16

c = 300 mg

Substituting c = 300 into the equation and solving for A

A = 0.06 * 300 +3.69

A = 18 + 3.69

A = 21.69

Therefore 21.69 g of compound will be produced

7 0

2 years ago

Measurements of the sodium content in samples of two brands of chocolate bar yield the following results (in grams):

Tpy6a [65]

Answer:

98% confidence interval for the difference μX−μY = [ 0.697 , 7.303 ] .

Step-by-step explanation:

We are give the data of Measurements of the sodium content in samples of two brands of chocolate bar (in grams) below;

Brand A : 34.36, 31.26, 37.36, 28.52, 33.14, 32.74, 34.34, 34.33, 29.95

Brand B : 41.08, 38.22, 39.59, 38.82, 36.24, 37.73, 35.03, 39.22, 34.13, 34.33, 34.98, 29.64, 40.60

Also, $\mu_X$ represent the population mean for Brand B and let $\mu_Y$ represent the population mean for Brand A.

Since, we know nothing about the population standard deviation so the pivotal quantity used here for finding confidence interval is;

P.Q. = $\frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ~ $t_n__1+n_2-2$

where, $Xbar$ = Sample mean for Brand B data = 36.9

$Ybar$ = Sample mean for Brand A data = 32.9

$n_1$ = Sample size for Brand B data = 13

$n_2$ = Sample size for Brand A data = 9

$s_p = \sqrt{\frac{(n_1-1)s_X^{2}+(n_2-1)s_Y^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(13-1)*10.4+(9-1)*7.1 }{13+9-2} }$ = 3.013

Here, $s^{2}_X$ and $s^{2} _Y$ are sample variance of Brand B and Brand A data respectively.

So, 98% confidence interval for the difference μX−μY is given by;

P(-2.528 < $t_2_0$ < 2.528) = 0.98

P(-2.528 < $\frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < 2.528) = 0.98

P(-2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ < $(Xbar -Ybar) -(\mu_X-\mu_Y)$ < 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ ) = 0.98

P( (Xbar - Ybar) - 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ < $(\mu_X-\mu_Y)$ < (Xbar - Ybar) + 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ ) = 0.98

98% Confidence interval for μX−μY =

[ (Xbar - Ybar) - 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ , (Xbar - Ybar) + 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ ]

[ $(36.9 - 32.9)-2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9}$ , $(36.9 - 32.9)+2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9}$ ]

[ 0.697 , 7.303 ]

Therefore, 98% confidence interval for the difference μX−μY is [ 0.697 , 7.303 ] .

4 0

3 years ago

Which reason best describes why you can divide any number by 100 by moving the decimal point two places to the left?

11111nata11111 [884]

The last choice is the reason, but to add to this, you are taking a value and breaking it into groups of 100( which is 10 groups of 10). Each place value in our decimal system naturally is based on a system of tens! Dividing by 100, is 2 groups of tens (2 decimal moves).

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4 years ago

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6 divided by 7.6 times 44

Delvig [45]

Answer:55.73333333333

Step-by-step explanation:

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3 years ago